When an AC source is connected across a 12.0 - resistor, the rms current in the resistor is 8.00 A. Find (a) the rms voltage across the resistor, (b) the peak voltage of the source, (c) the maximum current in the resistor, and (d) the average power delivered to the resistor

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A: Resistance, R = 150 ohm  I rms = 0.15 A

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A: Electric current

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A: Here, We know that Vrms=110 V and R=1.26 x 103 ΩA)The maximum potential difference across resistance…

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A: Given, V=V0sin2πft Frequency f = 14.5 Hz   We know the expression for voltage is  V=IR

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A: Peak voltage, Vp = 103.32 VResistance, R = 85 ΩRMS current, Irms = ?

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Q: A 2.62 ko resistor is connected to an AC voltage source with an rms voltage of 230 V. HINT (a) What…

A: max potential = 1.414 x V r m s  Vr m s = 230 volt R = 2620 Ω Imax = R / VPEAK

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A: Given  The emf of an ac source  v(t) =VosinωtThe voltage Vo              = 100 V.The angular voltage…

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A: Please see the answer in step 2

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A: Given that, Capacitor, C=40 µF Erms =200 V Frequency,f=50Hz

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A: V=200v f=1100hz Irms=4.3A Vrms=141.42v

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A: Note: Since you have posted a question with multiple sub-parts, we will solve the first three…

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A: Given : Peak voltage of an AC source (Vo) = 102 V

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A: XL=inductive reactance=W×L Z'=impedance

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Q: A capacitor is connected across an ac generator whose frequency is 750 Hz and whose peak output…

A: Irms = 3.1A  Vrms = peak voltage/ √(2) = 210 / √(2) = 148.5 Volt Frequency of ac generator (f) =…

Q: An AC voltage source and a resistor are connected in series to make up a simple AC circuit. If the…

A: Given,The source voltage, V = V0 sin (2πft)Frequency, f = 14 HzThe current, I = 0.54 I0we know,V =…

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Q: When an AC source is connected across a 10.0- resistor, the rms current in the resistor is 7.38 A.…

A: Given that-Resistance, R= 10.0ΩRMS current, Irms= 7.38AThe rms voltage, Vrms=Irms×R=7.38A×10.0Ω=73.8…