When a volleyball coach releases a volleyball from a height of 2 m above the gym floor, it falls to the floor and bounces back to two-thirds the same height. When it is in contact with the floor, the lower side of the ball is temporarily flattened. Suppose the maximum depth of the dent is 1 cm. (Assume the positive direction is upward.) 1. Determine the acceleration of the ball (in m/s2) while it is in contact with the floor and compressing. (Indicate the direction with the sign of your answer.) 2. Determine the velocity of the ball (in m/s) as it leaves the floor on the rebound. (Indicate the direction with the sign of your answer.) 3. What If? If instead of dropping the ball, the coach throws it down (from some unknown height) with such a speed that it bounces back up to a height three times its original height, determine the new acceleration of the ball (in m/s2) while in contact with the floor and expanding. (Indicate the direction with the sign of your answer.)
When a volleyball coach releases a volleyball from a height of 2 m above the gym floor, it falls to the floor and bounces back to two-thirds the same height. When it is in contact with the floor, the lower side of the ball is temporarily flattened. Suppose the maximum depth of the dent is 1 cm. (Assume the positive direction is upward.)
1. Determine the acceleration of the ball (in m/s2) while it is in contact with the floor and compressing. (Indicate the direction with the sign of your answer.)
2. Determine the velocity of the ball (in m/s) as it leaves the floor on the rebound. (Indicate the direction with the sign of your answer.)
3. What If? If instead of dropping the ball, the coach throws it down (from some unknown height) with such a speed that it bounces back up to a height three times its original height, determine the new acceleration of the ball (in m/s2) while in contact with the floor and expanding. (Indicate the direction with the sign of your answer.)
Step by step
Solved in 2 steps with 2 images
