When a plant or animal dies, its 14C content decreases with a half-life oft¹/2 = 5730 years. If an archaeologist find an ancient fire-pit containingpartially consumed firewood and the 14C content of the wood is 15% of what itwould be for a similar carbon sample from a present day tree, what is theapproximate age of the ancient site?24.96.91.88Enter your numerical result below, in units of years. Aim for a precision of 2significant figures.Your Answer:Answer

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1. The mass of a nucleus of plutonium (Pu23994) is 238.990396 u. Show that the binding energy per nucleon for plutonium is 7.6 MeV (show your work on scratch papers). 2. A radioactive isotope of an element decays with half-life 10 minutes. If originally there are 64 atoms in a sample of the element, what is the time that should pass until only one atom of the element is left out? What is the decay constant k?
After a plant or animal dies, its 14C content decreases with a half-life of 5730 years. If an archaeologist finds an ancient firepit containing partially consumed firewood, and the 14C content of the wood is only 55.5% that of an equal carbon sample from a present-day tree, what is the age of the ancient site?
Radioactive substances follow a specific law of decay. Namely, if you have a sample of some radioactive isotope, the quantity left after a certain time, called the half-life and denoted T1/2, is one-half of what you had initially. If you wait a second half-life, then there will be half f what was left at the end of the first half-life. Since 1/2-1/2 = 1/4, you will have one-fourth of the original quantity left after two half-lives. You can continue with this procedure to find the fraction of the original sample that hasn't decayed after any number of half- lives. However, this would become quite cumbersome if you are interested in the quantity left after, say, 10 half-lives. In this case, the quantity you are looking for would be found by multiplying the original quantity by 10 factors or 1/2. To solve this problem, we use exponents. An exponent, a small number written above and to the right, tells you how many copies of a particular number are multiplied together. In our example,…
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Hello please someone help me answer this problem set, thank you! Part A: A particular smoke detector contains 1.05 μCi of 241Am241Am, with a half-life of 458 years. The isotope is encased in a thin aluminum container. Calculate the mass of 241 Am in grams in the detector. Express your answer numerically in grams. Part B: Fears of radiation exposure from normal use of such detectors are largely unfounded. Identify reasons why 241 Am smoke detectors are perfectly safe. Select all that apply a. The penetrating power of αα radiation is limited. b. Ions get trapped by electrodes. c. The amount of americium is very little. d. The number of αα particles leaving the case is low. e. The detector has a plastic cover. f. The detector is housed in an aluminum case.
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An ancient artifact is found to contain 240 g of carbon and has an activity of 479 decays/min. Part A Q Search What is the approximate age of the artifact, to the nearest thousand years? (The rate of decay of carbon in living matter is R 16 decays/(g. min).) Express your answer to the nearest thousand years. 15| ΑΣΦ Submit Part B What would its initial activity have been? Ro= Request Answer 15. ΑΣΦ P Pearson W ? ? y Copyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us | decays/min Revie 10:02 AM 12/12/2022
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