When a normal random variable Y is transformed to a standard normal random variable Z, the 3.4.1 _value of Z is 1 and 3.4.2 value is 0. The probability density function for a standard normal random variable is f(z) = 3.4.3 Y possesses the density function f(V) = {2(2- y), 0 < y< 2 0, elsewhere S2(2 –: with the mean = 2/3 and the variance = 2/9. Using we find that: P(\Y - µl < 20) = P(Y-< 0.9428) = P(-.2761 < Y < 1.609).
When a normal random variable Y is transformed to a standard normal random variable Z, the 3.4.1 _value of Z is 1 and 3.4.2 value is 0. The probability density function for a standard normal random variable is f(z) = 3.4.3 Y possesses the density function f(V) = {2(2- y), 0 < y< 2 0, elsewhere S2(2 –: with the mean = 2/3 and the variance = 2/9. Using we find that: P(\Y - µl < 20) = P(Y-< 0.9428) = P(-.2761 < Y < 1.609).
Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter4: Writing Linear Equations
Section: Chapter Questions
Problem 12CR
Related questions
Question
![When a normal random variable Y is transformed to a standard normal random variable Z, the
3.4.1
value of Z is 1 and
3.4.2
value is 0. The
probability density function for a standard normal random variable is f(z) =
3.4.3
Y possesses the density function
f(V) = {2(2-y), 0<ys2
0, elsewhere
with the mean = 2/3 and the variance = 2/9. Using
we find that:
P(\Y - µl < 20) :
(r -< 0.9428) = P(-.2761 < Y < 1.609).
= P
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa242d6fd-840d-45da-814b-d4dbfff686c9%2F0d350b0d-2583-4fe3-ba3d-6c90fb03ea96%2F7q887e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:When a normal random variable Y is transformed to a standard normal random variable Z, the
3.4.1
value of Z is 1 and
3.4.2
value is 0. The
probability density function for a standard normal random variable is f(z) =
3.4.3
Y possesses the density function
f(V) = {2(2-y), 0<ys2
0, elsewhere
with the mean = 2/3 and the variance = 2/9. Using
we find that:
P(\Y - µl < 20) :
(r -< 0.9428) = P(-.2761 < Y < 1.609).
= P
%3D
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