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When a mass of 2 kilograms is attached to a spring whose constant is 32 N/m, it comes to rest in the equilibrium position. Starting at t = 0, a force equal to f(t) = 102e-2t cos(4t) is applied to the system. Find the equation of motion in the absence of damping. -4t 3e 4 x(t) = e-4t3 2 Need Help? sin (4t) + sin (4t) + Read It Watch It -cos (4t) - cos (4t) X m

When a mass of 2 kilograms is attached to a spring whose constant is 32 N/m, it comes to rest in the equilibrium position. Starting at t = 0, a force equal to f(t) = 102e-2t cos(4t) is applied to the system. Find the equation of motion in the absence of damping. -4t 3e 4 x(t) = e-4t3 2 Need Help? sin (4t) + sin (4t) + Read It Watch It -cos (4t) - cos (4t) X m

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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When a mass of 2 kilograms is attached to a spring whose constant is 32 N/m, it comes to rest in the equilibrium position. Starting at t = 0, a force equal to f(t) = 102e-2t cos(4t) is applied to the system. Find the equation of motion in the absence of damping. x(t) = e-4t3 2 ³sin (4t) + sin(4t) + Need Help? Read It Watch It -4t 3e 4 -cos (4t) - cos (4t) X m
Transcribed Image Text:When a mass of 2 kilograms is attached to a spring whose constant is 32 N/m, it comes to rest in the equilibrium position. Starting at t = 0, a force equal to f(t) = 102e-2t cos(4t) is applied to the system. Find the equation of motion in the absence of damping. x(t) = e-4t3 2 ³sin (4t) + sin(4t) + Need Help? Read It Watch It -4t 3e 4 -cos (4t) - cos (4t) X m
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