When a man stands near the edge of an empty drainage ditch of depth 2.80 m, he can barely see the boundary between the opposite wall and bottom of the ditch as in Figure (a) shown below. The distance from his eyes to the ground is h = 1.92 m. (Assume ? = 31.8°.) (a) What is the horizontal distance d from the man to the edge of the drainage ditch?d = m(b) After the drainage ditch is filled with water as in Figure (b) shown above, what is the maximum distance x the man can stand from the edge and still see the same boundary?x = m In the diagram, a person stands at the edge of a flat surface, gazing into a deeper pit. The person is at a height \( h \) above the pit. The pit itself has a vertical depth of 2.80 meters. The horizontal distance from the person to the edge of the pit is \( d \).An angled line, representing the line of sight, extends from the person’s eyes to the bottom of the pit at an angle \( \theta \) with respect to the horizontal surface.- **Vertical height of the pit**: 2.80 meters- **Variables**: - \( h \): Height of the person above the pit - \( d \): Horizontal distance from the person to the pit's edge - \( \theta \): Angle of the line of sightThis setup could be used to discuss concepts such as angles of depression, trigonometry, or physics involving trajectory analysis. This image illustrates the concept of light refraction at the boundary between air and water, demonstrating how light bends when it passes from one medium into another. In the diagram:- A person stands at the edge of a body of water, looking into it.- A ray of light is depicted as a blue line. The light travels from the person, through the air, and then enters the water at an angle.- The angle where the light ray hits the water is labeled as \(\theta\).- The horizontal distance from the point the person is standing to where the light enters the water is labeled as \(x\).- The light ray bends at the interface between the air and water due to the change in medium, illustrating refraction.This visual aids in understanding how the angle of incidence and refraction can affect the path of light.

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When a man stands near the edge of an empty drainage ditch of depth 2.80 m, he can barely see the boundary between the opposite wall and bottom of the ditch as in Figure (a) shown below. The distance from his eyes to the ground is h = 1.92 m. (Assume ? = 31.8°.) (a) What is the horizontal distance d from the man to the edge of the drainage ditch? d = m (b) After the drainage ditch is filled with water as in Figure (b) shown above, what is the maximum distance x the man can stand from the edge and still see the same boundary? x = m

When a man stands near the edge of an empty drainage ditch of depth 2.80 m, he can barely see the boundary between the opposite wall and bottom of the ditch as in Figure (a) shown below. The distance from his eyes to the ground is h = 1.92 m. (Assume ? = 31.8°.) (a) What is the horizontal distance d from the man to the edge of the drainage ditch? d = m (b) After the drainage ditch is filled with water as in Figure (b) shown above, what is the maximum distance x the man can stand from the edge and still see the same boundary? x = m

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