When a hypothetical diatomic molecule having atoms 0.8890 nm apart undergoes a rotational transition from the |= 2 state to the next lower state, it gives up a photon having energy 8.850 * 10-* eV. When the molecule undergoes a vibrational transition from one energy state to the next lower energy state, it gives up 0.2540 eV. Find the force constant of this molecule.
When a hypothetical diatomic molecule having atoms 0.8890 nm apart undergoes a rotational transition from the |= 2 state to the next lower state, it gives up a photon having energy 8.850 * 10-* eV. When the molecule undergoes a vibrational transition from one energy state to the next lower energy state, it gives up 0.2540 eV. Find the force constant of this molecule.
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![When a hypothetical diatomic molecule having atoms 0.8890 nm apart undergoes a
rotational transition from the l= 2 state to the next lower state, it gives up a photon having
energy 8.850 * 10-* eV. When the molecule undergoes a vibrational transition from one
energy state to the next lower energy state, it gives up 0.2540 eV.
Find the force constant of this molecule.
O k'=30.22 N/m
k=31.05 N/m
k'=20.22 N/m
k'=31.55 N/m
k' =29.55 N/m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F36b91a4a-4e29-484f-baef-1f36c191036f%2F71118599-eba9-4747-83dc-12446857414b%2Ffl2cyp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:When a hypothetical diatomic molecule having atoms 0.8890 nm apart undergoes a
rotational transition from the l= 2 state to the next lower state, it gives up a photon having
energy 8.850 * 10-* eV. When the molecule undergoes a vibrational transition from one
energy state to the next lower energy state, it gives up 0.2540 eV.
Find the force constant of this molecule.
O k'=30.22 N/m
k=31.05 N/m
k'=20.22 N/m
k'=31.55 N/m
k' =29.55 N/m
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