When a hypothetical diatomic molecule having atoms 0.8860 nm apart undergoes a rotational transition from the I= 2 state to the next lower state, it gives up a photon having energy 8.850 * 10¯ª eV. When the molecule undergoes a vibrational transition from one energy state to the next lower energy state, it gives up 0.2560 eV. Find the force constant of this molecule.

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When a hypothetical diatomic molecule having atoms 0.8860 nm apart undergoes a rotational transition from the =
2 state to the next lower state, it gives up a photon having energy 8.850 * 10-4 eV. When the molecule undergoes a
vibrational transition from one energy state to the next lower energy state, it gives up 0.2560 eV.
Find the force constant of this molecule.
Transcribed Image Text:When a hypothetical diatomic molecule having atoms 0.8860 nm apart undergoes a rotational transition from the = 2 state to the next lower state, it gives up a photon having energy 8.850 * 10-4 eV. When the molecule undergoes a vibrational transition from one energy state to the next lower energy state, it gives up 0.2560 eV. Find the force constant of this molecule.
a) O k'= 22.22 N/m
b) O k'= 31.05 N/m
c) O k'= 30.22 N/m
d) O k'= 29.55 N/m
e) O k'=20.32 N/m
Transcribed Image Text:a) O k'= 22.22 N/m b) O k'= 31.05 N/m c) O k'= 30.22 N/m d) O k'= 29.55 N/m e) O k'=20.32 N/m
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