When a falling meteoroid is at a distance above the Earth's surface of 2.85 times the Earth's radius, what is itsacceleration due to the Earth's gravitation?Part 1 of 3 - ConceptualizeThe motion of the meteoroid, or its mass, makes no difference. The gravitational field, which is theacceleration, will be smaller than the surface value we are used to because of the greater distance.Part 2 of 3 - CategorizeThe Earth exerts its force on the meteoroid according to mg = GmM- /r so we see that acceleration ofgravity, g = GM- /r², follows an inverse-square law. At the surface, a distance of one Earth-radius (R-) fromthe center, it is 9.80 m/s². An altitude of 2.85 R- above the surface represents a distance of 3.85 R- from the center of the Earth, so theacceleration of gravity will be (3.85) = 14.82 times smaller.GME2GME2RE9.80 m/s2m/s².II||

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When a falling meteoroid is at a distance above the Earth's surface of 2.85 times the Earth's radius, what is its acceleration due to the Earth's gravitation?

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

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When a falling meteoroid is at a distance above the Earth's surface of 2.85 times the Earth's radius, what is its
acceleration due to the Earth's gravitation?
Part 1 of 3 - Conceptualize
The motion of the meteoroid, or its mass, makes no difference. The gravitational field, which is the
acceleration, will be smaller than the surface value we are used to because of the greater distance.
Part 2 of 3 - Categorize
The Earth exerts its force on the meteoroid according to mg = GmM- /r so we see that acceleration of
gravity, g = GM- /r², follows an inverse-square law. At the surface, a distance of one Earth-radius (R-) from
the center, it is 9.80 m/s².

An altitude of 2.85 R- above the surface represents a distance of 3.85 R- from the center of the Earth, so the
acceleration of gravity will be (3.85) = 14.82 times smaller.
GME
2
GME
2
RE
9.80 m/s2
m/s².
II
||

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