When a driver brakes an automobile, the friction between the brake drums and the brake shoes converts the car's kinetic energy to thermal energy. If a 1550-kg automobile traveling a 28 m/s comes to a halt, how much does the temperature rise in each of the four 8.0 kg iron brake drums? (The specific heat of iron is 448 J/(kg - °C).)

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Chapter1: Units, Trigonometry. And Vectors
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**Understanding Energy Conversion in Automotive Braking Systems**

When a driver brakes an automobile, the friction between the brake drums and the brake shoes converts the car's kinetic energy to thermal energy. If a 1550-kg automobile traveling at 28 m/s comes to a halt, how much does the temperature rise in each of the four 8.0 kg iron brake drums? (The specific heat of iron is 448 J/(kg·°C)).

**Open Ended Questions:**  
- How does this conversion of energy affect the wear and tear on brake components?
- What are other examples of energy conversion in vehicles?

**Need Help?**
Transcribed Image Text:**Understanding Energy Conversion in Automotive Braking Systems** When a driver brakes an automobile, the friction between the brake drums and the brake shoes converts the car's kinetic energy to thermal energy. If a 1550-kg automobile traveling at 28 m/s comes to a halt, how much does the temperature rise in each of the four 8.0 kg iron brake drums? (The specific heat of iron is 448 J/(kg·°C)). **Open Ended Questions:** - How does this conversion of energy affect the wear and tear on brake components? - What are other examples of energy conversion in vehicles? **Need Help?**
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