When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 17 kg, the acceleration of the object is 4 m/s. If the same force acts upon another object whose mass is 2 kg, what is this object's acceleration?

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**Physics Problem: Acceleration and Mass Relationship**

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**Problem Statement:**

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 17 kg, the acceleration of the object is 4 m/s². If the same force acts upon another object whose mass is 2 kg, what is this object's acceleration?

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**Solution:**

To solve this problem, we use the concept that acceleration \( a \) is inversely proportional to mass \( m \) when a constant force \( F \) is applied:

\[ a \propto \frac{1}{m} \]

Given:
- Mass of the first object, \( m_1 = 17 \, \text{kg} \)
- Acceleration of the first object, \( a_1 = 4 \, \text{m/s}^2 \)
- Mass of the second object, \( m_2 = 2 \, \text{kg} \)

Using the relationship of inverse proportionality, we can write:

\[ a_1 \times m_1 = a_2 \times m_2 \]

Substituting the known values:

\[ 4 \, \text{m/s}^2 \times 17 \, \text{kg} = a_2 \times 2 \, \text{kg} \]

Solving for \( a_2 \):

\[ a_2 = \frac{4 \times 17}{2} \]

\[ a_2 = \frac{68}{2} \]

\[ a_2 = 34 \, \text{m/s}^2 \]

Thus, the acceleration of the object with mass 2 kg is **34 m/s²**.

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**Additional Information:**

- The box icon with "m/s²" signifies that the answer should be entered in meters per second squared.
- The icons (x, recycle, and question mark) are generally used for navigation or additional options in educational interfaces. 

This problem helps in understanding how force, mass, and acceleration interact, which is crucial in Newtonian mechanics.
Transcribed Image Text:**Physics Problem: Acceleration and Mass Relationship** --- **Problem Statement:** When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 17 kg, the acceleration of the object is 4 m/s². If the same force acts upon another object whose mass is 2 kg, what is this object's acceleration? --- **Solution:** To solve this problem, we use the concept that acceleration \( a \) is inversely proportional to mass \( m \) when a constant force \( F \) is applied: \[ a \propto \frac{1}{m} \] Given: - Mass of the first object, \( m_1 = 17 \, \text{kg} \) - Acceleration of the first object, \( a_1 = 4 \, \text{m/s}^2 \) - Mass of the second object, \( m_2 = 2 \, \text{kg} \) Using the relationship of inverse proportionality, we can write: \[ a_1 \times m_1 = a_2 \times m_2 \] Substituting the known values: \[ 4 \, \text{m/s}^2 \times 17 \, \text{kg} = a_2 \times 2 \, \text{kg} \] Solving for \( a_2 \): \[ a_2 = \frac{4 \times 17}{2} \] \[ a_2 = \frac{68}{2} \] \[ a_2 = 34 \, \text{m/s}^2 \] Thus, the acceleration of the object with mass 2 kg is **34 m/s²**. ------ **Additional Information:** - The box icon with "m/s²" signifies that the answer should be entered in meters per second squared. - The icons (x, recycle, and question mark) are generally used for navigation or additional options in educational interfaces. This problem helps in understanding how force, mass, and acceleration interact, which is crucial in Newtonian mechanics.
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