When a capacitor is being charged, the instantaneous current i at time t is given by: i (10-e «C ), where C and R are constants. Given C=7x10*F , and R= 0.3×10ʻ. Calculate: (a) The instantaneous current when t=2.5seconds (b) The time for the instantaneous current to fall to 5.0Amperes (c) On a graph paper, sketch a curve of current against time from t =0 to 1 = 6.0seconds

icon
Related questions
Question
When a capacitor is being charged, the instantaneous current i at time ! is given by:
i = (10-e C ), where C and R are constants. Given C =7×10*F, and R= 0.3×10ʻ2.
Calculate:
(a) The instantaneous current when t= 2.5seconds
(b) The time for the instantaneous current to fall to 5.0Amperes
(c) On a graph paper, sketch a curve of current against time from t =0 to t = 6.0seconds
Transcribed Image Text:When a capacitor is being charged, the instantaneous current i at time ! is given by: i = (10-e C ), where C and R are constants. Given C =7×10*F, and R= 0.3×10ʻ2. Calculate: (a) The instantaneous current when t= 2.5seconds (b) The time for the instantaneous current to fall to 5.0Amperes (c) On a graph paper, sketch a curve of current against time from t =0 to t = 6.0seconds
Expert Solution
steps

Step by step

Solved in 5 steps with 1 images

Blurred answer