c. Iron is oxidized, and the oxidizing agent is CO.O d. Iron is oxidized, and the oxidizing agent is Fe2O3.When a 45.0 g sample of an alloy at 100.0 °C is dropped into 100.0 g of water at 25.0 °C, the final temperature is 37.0 °C.What is the specific heat of the alloy?The specific heat of H,O(1) is 4.184 J-g-1.°C-1.Data sheet and Periodic TableSelect one:O a. 0.423 J-g-1.°C-1Ob. 1.77 J-g-1.c-1O c.9.88 J-g-1.°C1O d. 48.8 J-g-1.°C-1The molar enthalpy of formation for H2O(1) is –-285.8 kJ-mol-1. Which expression describes the enthalpy change for the reaction:AH° = ?2H20(1)→2H2(g) + O2(g)

Given, 45.0g of an alloy at 100.0oC is dropped into 100.0g of water at 25oC. The final temperature of the mixture became ------ 37.0oC. What is the specific heat capacity of the alloy?The heat energy lost by the alloy = heat energy gained by water Heat energy lost by alloy=mass of alloy x its specific heat capacity x (Talloy-Tmixture) (T stands for temperature) Heat energy gained by water= mass of water x specific heat capacity of water x (Tmixture - Twater)Heat energy lost by alloy: Mass of alloy = 45.0g initial temperature of alloy = 100.0oC final temperature of mixture = 37.0oC Let the specific heat capacity of alloy is Cp. Heat energy lost by the alloy =45.0g ×Cp× (100.0-37.0)oC =2835g.°C x CpHeat energy gained by water: Given, mass of water = 100.0g Specific heat capacity of water = 4.184J/g.oC Change in temperature of water = (37.0-25.0)°C =12°C The amount of heat energy gained by water:mass of water ×specific heat capacity of water ×change in temperature of water=100.0g×4.184J/g.°C×(37.0-25.0)°C=5020.8JSince, The amount of heat energy lost by alloy = heat energy gained by water From the above expressions, 2835g. °C x Cp=5020.8J⇒Cp=5020.8J2835g.°C⇒Cp=1.77J/g.°CAnswer: Hence, specific heat capacity of the alloy is 1.77 J/g.oC. option b . is the correct answer.

Science

Chemistry

When a 45.0g sample of an alloy at 100.0 °C is dropped into 100.0 g of water at 25.0 °C, the final temperature is 37.0 °C. What is the specific heat of the alloy? The specific heat of H2O(1) is 4.184 J-g1.°C-1. Data sheet and Periodic Table Select one: O a. 0.423 J-g-1.°C-1 O b. 1.77 J-g-1.°C1 O .9.88 J-g-1.°C-1 d. 48.8 J-g1.°C-1

When a 45.0g sample of an alloy at 100.0 °C is dropped into 100.0 g of water at 25.0 °C, the final temperature is 37.0 °C. What is the specific heat of the alloy? The specific heat of H2O(1) is 4.184 J-g1.°C-1. Data sheet and Periodic Table Select one: O a. 0.423 J-g-1.°C-1 O b. 1.77 J-g-1.°C1 O .9.88 J-g-1.°C-1 d. 48.8 J-g1.°C-1

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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