When a 15.5 mL sample of a 0.407 M aqueous nitrous acid solution is titrated with a 0.329 M aqueous sodium hydroxide solution, what is the pH after 28.8 mL of sodium hydroxide have been added? pH =

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**Question:**

When a 15.5 mL sample of a 0.407 M aqueous nitrous acid solution is titrated with a 0.329 M aqueous sodium hydroxide solution, what is the pH after 28.8 mL of sodium hydroxide have been added?

**Answer:**

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**Explanation:**

This question involves a titration process, which is a common laboratory method of quantitative chemical analysis. It is used to determine the concentration of an identified analyte (in this case, nitrous acid) by reacting it with a solution of known concentration (sodium hydroxide).

Key elements include:
- Volume and molarity of the original nitrous acid solution.
- Volume and molarity of the sodium hydroxide solution being added.
- The calculation of the pH after the solution reaches a specific volume due to the titration process.

**Note:** No graphs or diagrams are present in the image provided.
Transcribed Image Text:**Question:** When a 15.5 mL sample of a 0.407 M aqueous nitrous acid solution is titrated with a 0.329 M aqueous sodium hydroxide solution, what is the pH after 28.8 mL of sodium hydroxide have been added? **Answer:** (Blank space for the answer) **Submit Answer** --- **Explanation:** This question involves a titration process, which is a common laboratory method of quantitative chemical analysis. It is used to determine the concentration of an identified analyte (in this case, nitrous acid) by reacting it with a solution of known concentration (sodium hydroxide). Key elements include: - Volume and molarity of the original nitrous acid solution. - Volume and molarity of the sodium hydroxide solution being added. - The calculation of the pH after the solution reaches a specific volume due to the titration process. **Note:** No graphs or diagrams are present in the image provided.
Expert Solution
Step 1

Nitrous acid is HNO2, a weak monoprotic acid with Ka = 6.92*10-4 (pKa = 3.16).

Sodium hydroxide is NaOH, a strong monoacidic base. 

The balanced equation for the neutralization reaction is:

HNO2(aq) + NaOH(aq)  NO2-(aq) + H2O(l) +Na+(aq)

 Since all the coefficients are 1, the required mole ratio is 1/1

Hence equal moles of HNO2(aq) and NaOH(aq) and the reactant with a smaller mole is the limiting reactant. 

 

 

 

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