When 4.61 grams of ice at – 20°C have absorbed 2500 calories of heat, what is the temperature of the resulting water? specific heat of ice = 0.50 cal/g °c specific heat of water = 1.0 cal/g °C

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter5: Gases, Liquids, And Solids
Section: Chapter Questions
Problem 5.86P: 5-86 Using the phase diagram of water (Figure 5-20), describe the process by which you can sublime 1...
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When 4.61 grams of ice at - 20°C have
absorbed 2500 calories of heat, what is the
temperature of the resulting water?
specific heat of ice = 0.50 cal/g°c
specific heat of water = 1.0 cal/g °C
latent heat of fusion = 80 cal /g
Transcribed Image Text:When 4.61 grams of ice at - 20°C have absorbed 2500 calories of heat, what is the temperature of the resulting water? specific heat of ice = 0.50 cal/g°c specific heat of water = 1.0 cal/g °C latent heat of fusion = 80 cal /g
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