When 4 moles of aluminum are allowed to react with an excess of chlorine gas, Cl₂, how many moles of aluminum chloride are produced? 2AI + 3Cl₂ → 2AICI 3 O 2 moles O 5 moles 4 moles 3 moles
When 4 moles of aluminum are allowed to react with an excess of chlorine gas, Cl₂, how many moles of aluminum chloride are produced? 2AI + 3Cl₂ → 2AICI 3 O 2 moles O 5 moles 4 moles 3 moles
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Stoichiometry Question
**Question:**
When 4 moles of aluminum are allowed to react with an excess of chlorine gas, \( \text{Cl}_2 \), how many moles of aluminum chloride are produced?
**Chemical Reaction Equation:**
\[ 2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3 \]
**Answer Choices:**
- 2 moles
- 5 moles
- 4 moles
- 3 moles
**Correct Answer:**
- 4 moles
**Explanation:**
According to the balanced chemical equation \( 2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3 \), 2 moles of aluminum react to form 2 moles of aluminum chloride. Therefore, if 4 moles of aluminum are present, they will produce 4 moles of aluminum chloride in the presence of excess chlorine gas.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff4db65e3-9c39-4835-b9af-3449176c4ba4%2Fefc51eca-e44b-40b0-98b7-620a9bd00260%2Figfex3b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Stoichiometry Question
**Question:**
When 4 moles of aluminum are allowed to react with an excess of chlorine gas, \( \text{Cl}_2 \), how many moles of aluminum chloride are produced?
**Chemical Reaction Equation:**
\[ 2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3 \]
**Answer Choices:**
- 2 moles
- 5 moles
- 4 moles
- 3 moles
**Correct Answer:**
- 4 moles
**Explanation:**
According to the balanced chemical equation \( 2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3 \), 2 moles of aluminum react to form 2 moles of aluminum chloride. Therefore, if 4 moles of aluminum are present, they will produce 4 moles of aluminum chloride in the presence of excess chlorine gas.
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