When 36.1 g of NH3 (MM = 17.03 g/mol) decompose, 171 kJ of energy is absorbed. Calculate AHXN in kJ for the reaction of 2 moles of NH3 according to this balanced equation: 2 NH3(g) → N2(g) + 3 H2(g) O 40.3 kJ O 342 kJ O 161 kJ O 80.7 kJ

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Chapter1: Chemical Foundations
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When 36.1 g of NH3 (MM = 17.03 g/mol) decompose, 171 kJ of energy is absorbed. Calculate ΔHrxn in kJ for the reaction of 2 moles of NH3 according to this balanced equation:

2 NH3(g) → N2(g) + 3 H2(g)

When 36.1 g of NH₃ (MM = 17.03 g/mol) decompose, 171 kJ of energy is absorbed. Calculate ΔH_rxn in kJ for the reaction of 2 moles of NH₃ according to this balanced equation:

\[ 2 \text{ NH}_3(\text{g}) \rightarrow \text{N}_2(\text{g}) + 3 \text{ H}_2(\text{g}) \]

Options:
- 40.3 kJ
- 342 kJ
- 161 kJ
- 80.7 kJ

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Transcribed Image Text:When 36.1 g of NH₃ (MM = 17.03 g/mol) decompose, 171 kJ of energy is absorbed. Calculate ΔH_rxn in kJ for the reaction of 2 moles of NH₃ according to this balanced equation: \[ 2 \text{ NH}_3(\text{g}) \rightarrow \text{N}_2(\text{g}) + 3 \text{ H}_2(\text{g}) \] Options: - 40.3 kJ - 342 kJ - 161 kJ - 80.7 kJ There are no graphs or diagrams in this image.
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