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What's wrong with this argument? Suppose x and y represent two real numbers, where x > y. 2 > 1 This is a true statement. 2(y – x) > 1(y – x) Multiply both sides by y - x. 2y – 2x > y - x Use the distributive property. y - 2x > -x Subtract y from both sides. y > x Add 2x to both sides. The final inequality, y > x, is impossible because we were initially given x > y.

What's wrong with this argument? Suppose x and y represent two real numbers, where x > y. 2 > 1 This is a true statement. 2(y – x) > 1(y – x) Multiply both sides by y - x. 2y – 2x > y - x Use the distributive property. y - 2x > -x Subtract y from both sides. y > x Add 2x to both sides. The final inequality, y > x, is impossible because we were initially given x > y.

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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What's wrong with this argument? Suppose x and y represent two real numbers, where x > y. 2 > 1 This is a true statement. 2(y – x) > 1(y – x) Multiply both sides by y - x. 2y – 2x > y - x Use the distributive property. y - 2x > -x Subtract y from both sides. y > x Add 2x to both sides. The final inequality, y > x, is impossible because we were initially given x > y.
Transcribed Image Text:What's wrong with this argument? Suppose x and y represent two real numbers, where x > y. 2 > 1 This is a true statement. 2(y – x) > 1(y – x) Multiply both sides by y - x. 2y – 2x > y - x Use the distributive property. y - 2x > -x Subtract y from both sides. y > x Add 2x to both sides. The final inequality, y > x, is impossible because we were initially given x > y.
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