What's the quadratic approximation of the function f(x) = x² sin (2x) at the point x = π/4? O f(x)≈ 0.62 +1.57(x - π/4) - 0.47(x f(x) 0.58 +1.53(x - π/4) - 0.34(x f(x) 0.62 +1.43(x - π/4) - 0.34(x ≈ f(x)≈ 0.62 +1.57(x – π/4) — 0.34(x

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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What's the quadratic approximation of the
function f(x) = x² sin(2x) at the point
x = π/4?
O
f(x) ≈ 0.62 +1.57(x – π/4) — 0.47(x
f(x)≈ 0.58+1.53(x − π/4) – 0.34(x
f(x)≈ 0.62 +1.43(x − π/4) — 0.34(x
f(x) ≈ 0.62 +1.57(x – π/4) — 0.34(x
Transcribed Image Text:What's the quadratic approximation of the function f(x) = x² sin(2x) at the point x = π/4? O f(x) ≈ 0.62 +1.57(x – π/4) — 0.47(x f(x)≈ 0.58+1.53(x − π/4) – 0.34(x f(x)≈ 0.62 +1.43(x − π/4) — 0.34(x f(x) ≈ 0.62 +1.57(x – π/4) — 0.34(x
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