What's the area of the sector of a circle if the radius is 18 in and the central angle is 172°? in

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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 Round the answer to the hundredth place.

**Problem Statement:**

Find the area of a sector of a circle if the radius is 18 inches and the central angle is 172 degrees.

**Solution:**

To find the area of a sector, we use the formula:

\[
\text{Area of sector} = \frac{\theta}{360} \times \pi r^2
\]

where:
- \(\theta\) is the central angle in degrees,
- \(r\) is the radius of the circle.

Given:  
- \(\theta = 172^\circ\),
- \(r = 18\) inches.

Calculate the area of the sector:

1. Plug the values into the formula:

\[
\text{Area of sector} = \frac{172}{360} \times \pi \times (18)^2
\]

2. Simplify the calculation:

\[
\text{Area of sector} = \frac{172}{360} \times 3.1416 \times 324
\]

3. Continue with arithmetic to find the final result.

The area of the sector will be displayed in the box in \(\text{in}^2\).
Transcribed Image Text:**Problem Statement:** Find the area of a sector of a circle if the radius is 18 inches and the central angle is 172 degrees. **Solution:** To find the area of a sector, we use the formula: \[ \text{Area of sector} = \frac{\theta}{360} \times \pi r^2 \] where: - \(\theta\) is the central angle in degrees, - \(r\) is the radius of the circle. Given: - \(\theta = 172^\circ\), - \(r = 18\) inches. Calculate the area of the sector: 1. Plug the values into the formula: \[ \text{Area of sector} = \frac{172}{360} \times \pi \times (18)^2 \] 2. Simplify the calculation: \[ \text{Area of sector} = \frac{172}{360} \times 3.1416 \times 324 \] 3. Continue with arithmetic to find the final result. The area of the sector will be displayed in the box in \(\text{in}^2\).
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