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- SAMPLE PROBLEMS & SOLUTIONS Example 1: The interacting potential energy between two ions is represented by the following expression: -1.252 5.625 x 10-6 U = ..Eqn(1) r8 Where (r) is the distance in nm (1nm = 10-m) (U) is in kJ Calculate: a) The equilibrium distance ro in nm. b) The minimum bond energy in kJ. c) The maximum interionic force for the bond in kN.Please don't provide handwriting solutionMaterials with valence electrons fewer than four electrons are generally conductors. Why is it? a. (The answer cannot be found on the other choices.) b. For materials with fewer than three valence electrons, less or insignificant electric field is produced in the conductor. This is the reason why the electric field inside a conductor is zero. c. Originally, these materials have eight valence electrons. Greater than four of these valence electrons became free electrons and fewer than four valence electrons remained. This is why conductors have more free electrons at room temperature. d. Valence electrons in these materials need less energy gap is needed to be overcame to dislodge them from their parent atoms to become free electrons. Hence, conductors have overlapping conduction and valence bands.
- Consider the following doping profile in the figure below: N₁- Na N. -x0 -N a x хо Figure 1: Problem 3 Doping Profile Sketch the charge density p(x), you may assume an abrupt junction Derive an expression for the electric fieldQUESTION 3 For 3-dimensional rotational motion of an electron, the total angular momentum... depends on I and m. has a degeneracy of 21. equals ħ/1(1+ 1). none are correctA K* and a CI- ion are separated by 0.52 nm. Find the Coulomb component of the binding energy at that distance. Give your answer in electron-volts. (Please include the appropriate sign.) A positive binding energy would mean the ions are unbound and a negative binding energy means they are bound. Note: For this homework problem, round your answer to 2 decimal places.