What would be the output generated by the following code? public class Main implements Runnable { String strl, str2; public void run() { for (int i = { } 0; i<10; i++) strl = "Welcome"; str2 = "To Java"; System.out.println (strl + " " + str2 + " ") } | public static void main(String args[]) { Main run = new Main (); = Thread obj1 = new Thread (run); Thread obj2 new Thread(); objl.start(); obj2.run(); } A. Prints "Welcome To Java" line-by-line for 20 times. B. Prints "Welcome To Java" line-by-line for 10 times. C. Prints "Welcom to Java" line-by-line for 20 times. D. Enters into Deadlock. E. Since obj2 did not call start() method so, throws an Exception
What would be the output generated by the following code? public class Main implements Runnable { String strl, str2; public void run() { for (int i = { } 0; i<10; i++) strl = "Welcome"; str2 = "To Java"; System.out.println (strl + " " + str2 + " ") } | public static void main(String args[]) { Main run = new Main (); = Thread obj1 = new Thread (run); Thread obj2 new Thread(); objl.start(); obj2.run(); } A. Prints "Welcome To Java" line-by-line for 20 times. B. Prints "Welcome To Java" line-by-line for 10 times. C. Prints "Welcom to Java" line-by-line for 20 times. D. Enters into Deadlock. E. Since obj2 did not call start() method so, throws an Exception
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
.
![What would be the output generated by the following code?
public class Main implements Runnable
{
String strl, str2;
public void run ()
{
for (int i = 0; i <10; i++)
{
}
}
strl
str2
"Welcome";
"To Java";
System.out.println (strl + " " + str2 +
=
=
} |
public static void main(String args[])
{
Main run = new Main ();
Thread obj1 = new Thread (run);
Thread obj2 new Thread();
objl.start();
obj2.run();
=
}
A. Prints "Welcome To Java" line-by-line for 20 times.
B. Prints "Welcome To Java" line-by-line for 10 times.
C. Prints "Welcom to Java" line-by-line for 20 times.
D. Enters into Deadlock.
E. Since obj2 did not call start() method so, throws an Exception
"1
");](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff0e4299c-5fab-42f0-b90e-4ed1bc3cc6dc%2F71289789-0324-4f32-aae8-c2415ea4f7d5%2Fzaa9nti_processed.png&w=3840&q=75)
Transcribed Image Text:What would be the output generated by the following code?
public class Main implements Runnable
{
String strl, str2;
public void run ()
{
for (int i = 0; i <10; i++)
{
}
}
strl
str2
"Welcome";
"To Java";
System.out.println (strl + " " + str2 +
=
=
} |
public static void main(String args[])
{
Main run = new Main ();
Thread obj1 = new Thread (run);
Thread obj2 new Thread();
objl.start();
obj2.run();
=
}
A. Prints "Welcome To Java" line-by-line for 20 times.
B. Prints "Welcome To Java" line-by-line for 10 times.
C. Prints "Welcom to Java" line-by-line for 20 times.
D. Enters into Deadlock.
E. Since obj2 did not call start() method so, throws an Exception
"1
");
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