What will be the result of the following query? SELECT count(*) FROM enrollment GROUP BY courseid;

Computer Networking: A Top-Down Approach (7th Edition)
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Observe the **ENROLLMENT AND COURSE** database:

**ENROLLMENT**

| EmpID | EmpName | CourseID |
|-------|---------|----------|
| 111   | Joe     | AMG      |
| 222   | Bob     | AMG      |
| 333   | Lisa    | PMG      |
| 444   | Sue     | AMG      |

**COURSE**

| CourseID | CourseName          |
|----------|---------------------|
| AMG      | Anger Management    |
| PMG      | Project Management  |

The image displays two tables from a database. 

1. **ENROLLMENT Table**:
   - Columns: `EmpID`, `EmpName`, and `CourseID`.
   - Lists employees and the courses they are enrolled in, e.g., Joe with EmpID 111 is enrolled in Anger Management.

2. **COURSE Table**:
   - Columns: `CourseID` and `CourseName`.
   - Provides the names of courses corresponding to their IDs, e.g., AMG stands for Anger Management.
Transcribed Image Text:Observe the **ENROLLMENT AND COURSE** database: **ENROLLMENT** | EmpID | EmpName | CourseID | |-------|---------|----------| | 111 | Joe | AMG | | 222 | Bob | AMG | | 333 | Lisa | PMG | | 444 | Sue | AMG | **COURSE** | CourseID | CourseName | |----------|---------------------| | AMG | Anger Management | | PMG | Project Management | The image displays two tables from a database. 1. **ENROLLMENT Table**: - Columns: `EmpID`, `EmpName`, and `CourseID`. - Lists employees and the courses they are enrolled in, e.g., Joe with EmpID 111 is enrolled in Anger Management. 2. **COURSE Table**: - Columns: `CourseID` and `CourseName`. - Provides the names of courses corresponding to their IDs, e.g., AMG stands for Anger Management.
**Question:**

What will be the result of the following query?

```sql
SELECT count(*) FROM enrollment
GROUP BY courseid;
```

**Options:**

- ○ numbers 3 and 1
- ○ number 3
- ○ numbers 4, 3, and 1
- ○ number 4
- ○ number 1
Transcribed Image Text:**Question:** What will be the result of the following query? ```sql SELECT count(*) FROM enrollment GROUP BY courseid; ``` **Options:** - ○ numbers 3 and 1 - ○ number 3 - ○ numbers 4, 3, and 1 - ○ number 4 - ○ number 1
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