What will be the output of the following C++ code? #include using namespace std; int main() { int i, j; j = 10; i = (j++, j + 100, 999 + j); cout << i; return 0; } a) 1000 b) 11 c) 1010 d) 1001
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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int main()
{
int i, j;
j = 10;
i = (j++, j + 100, 999 + j);
cout << i;
return 0;
}
a) 1000
b) 11
c) 1010
d) 1001
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- Look at the following C++ code and comment each line about how it works with pointer. int i = 33; double d = 12.88; int * iPtr = &i; double * dPtr = &d; // iPtr = &d; // dPtr = &i; // iPtr = i; // int j = 99; iPtr = &j; //This is the C code I have so far #include <stdio.h> #include <stdlib.h> struct employees { char name[20]; int ssn[9]; int yearBorn, salary; }; // function to read the employee data from the user void readEmployee(struct employees *emp) { printf("Enter name: "); gets(emp->name); printf("Enter ssn: "); for (int i = 0; i < 9; i++) scanf("%d", &emp->ssn[i]); printf("Enter birth year: "); scanf("%d", &emp->yearBorn); printf("Enter salary: "); scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() { // creating the pointer struct employees *emp = malloc(sizeof(struct employees)); // function to read the data readEmployee(emp); // returning the data return emp; } // function to print the employee data to console void display(struct employees *e) { printf("%s", e->name); printf(" %d%d%d-%d%d-%d%d%d%d",…#include using namespace std; int main() int x=1,y=2; for (int i=0; i<3; i++) e{ x=x*y; 8{ } cout<#include using namespace std; void some_action_1(int); int main() { cout<C++ Programmingint func(int a, int b) { return (aThis assignment is not graded, I just need to understand how to do it. Please help, thank you! Language: C++ Given: Main.cpp #include #include "Shape.h" using namespace std; void main() { /////// Untouchable Block #1 ////////// Shape* shape; /////// End of Untouchable Block #1 ////////// /////// Untouchable Block #2 ////////// if (shape == nullptr) { cout << "What shape is this?! Good bye!"; return; } cout << "The perimeter of your " << shape->getShapeName() << ": " << shape->getPerimeter() << endl; cout << "The area of your " << shape->getShapeName() << ": " << shape->getArea() << endl; /////// End of Untouchable Block #2 //////////} Shape.cpp string Shape::getShapeName() { switch (mShapeType) { case ShapeType::CIRCLE: return "circle"; case ShapeType::SQUARE: return "square"; case ShapeType::RECTANGLE: return "rectangle"; case…#177. Run code in C++ compiler #include using namespace std; void square (int *x) { *x = (*x + 1) * (*x); } int main ( ) { int num = 10; square(&num); cout << num; return e; }#include<iostream>using namespace std;void main(){double pi = 0, denominator = 1;int counter = 999999;for (int x = 0; x < counter; x++){if (x % 2 != 0){pi = pi - (1 / denominator);}else{pi = pi + (1 / denominator);}denominator = denominator + 2;}pi = pi * 4;cout << " So the computed value of a PI is = " << pi << endl;cout << " ";//return 0;system("pause");} Note: This a program called ComputePI to compute the value of π Tutor just have to Modify This program to use nested-if (if ... else if ... else if ... else) instead. Explain by applying a double line commentc++complete and change #include <iostream>using namespace std; int sumbyrow(int* m, int ncol, int row){int total = 0;for (int i = 0 i < ncol; i++) {total += m[row * ncol + i];}return total; } int sumBCol(int* m, int nrow, int ncol, int col){int total = 0;for (int j = 0; < j nrow; j++) {total += m[j * ncol + col]; }return total;}int sumBYLeftDiag(int* m, int ncol){int total = 0;for (int i = 0, j = ncol - 1; i < ncol && j >= 0; i++, j--) {total += m[i * ncol + j];}return total;}bool hasDuplicates(int* m, int row) {int flatArray[row * row];int k = 0for (int i = 0; i < row; i++) {for (int j = 0; j < row; j++) {flatArray[k++] = m[i * row + j]; }}for (int i = 0; i < (row * row); i++) {for (int j = i + 1; j < (row * row); j++) {if (flatArray[i] == flatArray[j])return true; }}return flase;} bool isMagicMatrix(int* m, int nrow, int ncol) { if (hasDuplicate(m, nrow), int ncol{return false; }if (sumByleftDiag(m, nrow) != sumByRightDiag(m, nrow)) {return…#176. Run code in C++ compiler #include using namespace std; int add(int a, int b); int main() { int i 5, j = 6; cout <« add (i, j) « endl; return 0; } int add(int a, int b ) { int sum = a + b; a = 7; return a + b;C++ Coding: Arrays Given the following code and program output: #include <iostream>using namespace std;double average(const int g[], const int& CAP);void output(const int *g, const int& GRADES, const double& GPA);int main() { const int NUM_GRADES = 5; int grades[NUM_GRADES] = {10, 15, 20, 25, 30}; //average function is called by output function output(grades, NUM_GRADES, average(grades, NUM_GRADES)); return 0;} Example Output: 10, 15, 20, 25, 30GPA: 20 Code function definitions for average() and output(): average() accepts the array and its size as input, and returns the average grade with two decimal places. output() accepts the original array, the array's size, and GPA (generated from the average function) as function parameters. 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