What will be the osmotic pressure exerted by an aqueous solution of 500 mL volume at 25°C if it contains 12.54g dissolved magnesium chloride?

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**Osmotic Pressure Calculation**

*Problem Statement:*

What will be the osmotic pressure exerted by an aqueous solution of 500 mL volume at 25°C if it contains 12.54 g of dissolved magnesium chloride?

*Explanation:*

To solve this problem, we'll need to use the formula for osmotic pressure:

\[ \pi = iMRT \]

where:
- \( \pi \) is the osmotic pressure,
- \( i \) is the van’t Hoff factor,
- \( M \) is the molarity of the solution,
- \( R \) is the ideal gas constant (0.0821 L·atm/mol·K),
- \( T \) is the temperature in Kelvin.

**Steps to solve:**

1. **Determine the molarity (\( M \)) of the solution:**
   - Calculate the moles of magnesium chloride (MgCl\(_2\)). The molar mass of MgCl\(_2\) is approximately 95.21 g/mol.
   - Convert the mass of MgCl\(_2\) to moles: 
     \[ \text{moles of MgCl}_2 = \frac{12.54 \, \text{g}}{95.21 \, \text{g/mol}} \]
   - Convert the volume from mL to L: 
     \[ 500 \, \text{mL} = 0.500 \, \text{L} \]
   - Molarity \( M \) = \(\frac{\text{moles of solute}}{\text{volume of solution in L}}\).

2. **Identify the van't Hoff factor (\( i \)) for MgCl\(_2\):**
   - MgCl\(_2\) dissociates into three ions: \( \text{Mg}^{2+} \) and \( 2 \, \text{Cl}^- \), so \( i = 3 \).

3. **Calculate the osmotic pressure using the formula:**
   - Convert the temperature to Kelvin: \( T = 25°C + 273.15 \).
   - Substitute the values into the osmotic pressure formula to find \( \pi \).

Use this framework to perform the calculations and arrive at the final osmotic pressure.
Transcribed Image Text:**Osmotic Pressure Calculation** *Problem Statement:* What will be the osmotic pressure exerted by an aqueous solution of 500 mL volume at 25°C if it contains 12.54 g of dissolved magnesium chloride? *Explanation:* To solve this problem, we'll need to use the formula for osmotic pressure: \[ \pi = iMRT \] where: - \( \pi \) is the osmotic pressure, - \( i \) is the van’t Hoff factor, - \( M \) is the molarity of the solution, - \( R \) is the ideal gas constant (0.0821 L·atm/mol·K), - \( T \) is the temperature in Kelvin. **Steps to solve:** 1. **Determine the molarity (\( M \)) of the solution:** - Calculate the moles of magnesium chloride (MgCl\(_2\)). The molar mass of MgCl\(_2\) is approximately 95.21 g/mol. - Convert the mass of MgCl\(_2\) to moles: \[ \text{moles of MgCl}_2 = \frac{12.54 \, \text{g}}{95.21 \, \text{g/mol}} \] - Convert the volume from mL to L: \[ 500 \, \text{mL} = 0.500 \, \text{L} \] - Molarity \( M \) = \(\frac{\text{moles of solute}}{\text{volume of solution in L}}\). 2. **Identify the van't Hoff factor (\( i \)) for MgCl\(_2\):** - MgCl\(_2\) dissociates into three ions: \( \text{Mg}^{2+} \) and \( 2 \, \text{Cl}^- \), so \( i = 3 \). 3. **Calculate the osmotic pressure using the formula:** - Convert the temperature to Kelvin: \( T = 25°C + 273.15 \). - Substitute the values into the osmotic pressure formula to find \( \pi \). Use this framework to perform the calculations and arrive at the final osmotic pressure.
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