What will be the major organic product from the dehydration of 2-butanol in thepresence of a strong acid and high temperature? **Question:**What will be the major organic product from the dehydration of 2-butanol in the presence of a strong acid and high temperature?**Options:**A) butane-1,2-diolB) butaneC) 2-butanoneD) 2-buteneE) 1-butene---**Explanation:**In this question, we are asked to identify the major organic product formed when 2-butanol undergoes dehydration in the presence of a strong acid and high temperature. This reaction typically involves the elimination of a water molecule (dehydration) and the formation of a double bond, resulting in an alkene as the major product.The correct answer is likely found within the options that include alkenes, such as D) 2-butene or E) 1-butene. The reaction conditions favor the formation of the more substituted alkene, following Zaitsev's rule, which predicts that the more stable (more substituted) alkene will be the predominant product.Therefore, the major product is expected to be D) 2-butene.

Dehydration of alcohol: In dehydration of an alcohol, there is the formation of alkene is as the product. In this reaction, the alcohol is heated (i.e. high temperature) in presence of strong acid, and with the loss of water molecule, there is the formation of alkene as the product. In the given options (A), (B), and (C) can not be the correct option because they are not alkene. Now check the option (D) and (E). The mechanism of the reaction is as follows: The mechanism proceeds by E2 mechanism. In the first step, the lone pair of O attack the H of the sulphuric acid, and in the next step, the anion formed abstracts the H to form the alkene. The more substituted alkene is the major product. So, the product formed is 2-butene. Therefore the correct option is (D).