What will be the data stored in the destination address B3:4 of the following when the input is true? Input -AND- BITWISE AND Source A B3:51 1111000011001111 Source B B3:72 1100110000101100 Destination в34 0000000000000000
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- Consider the following runtime stack: BEFORE 00001000 00000006 ESP 00000FFC 00000FF 8 00000FF 4 00000FF0 What would be the value of ESP after pushing the 32-bit value shown below onto the stack? 000000A5 O 00001020 O 00000FF8 O 00000FFC O 000000A5(c) Figure Q3(c)(i) shows a register and Figure Q3(c)(ii) shows the input waveforms (CLOCK and Data in) to the circuit. A1 A9 A10 A2 Function generator A3 A11 A12 AS A13 A6 A14 A7 A15 Data in Bop.7) ip.r 82p.7) Logic analyser U1 U2 U3 U4 UO 6. 1. 6 1 6 INVERTER 3 CLK 3 CLK oCLK CLK 5 K K 5 K K 4027 Clock Function generator Figure Q3(c)(i) (i) Determine the type of register as shown in Figure Q3(c)(i).USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…
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- Perform floating point binary addition to the following: A: 1 10000011 10110111010000000000000 B: 0 10000000 10010011000100101000000 The result of A+B must be in be in 32-bit floating point. You can also check the answer in decimal.bit numbers and store lower byte of the result in accumulator A and higher byte in accumulator B.. Similarly lower byte of 2nd number is stored in R2 and higher byte in R3. Now subtract these two 16 numbers in the RAM such that lower byte of 1t number is stored in R0 and higher byte in RI. manipulate 16 bits numbers as well. Write an assembly language program that stores two 16 bits 8051 is an 8-bit microcontroller that performs arithmetic on 8-bit numbers. However, we can Question#3: 8051 is an 8-bit microcontroller that performs arithmetic on 8-bit numbers. HoweveWrite a VHDL code for the following simple logic circuit. D- X1 X2 f X3
- give the final result of operation that appears onto OUT-Reg. after convert the whole program below into Op-code? Address OH 1H 3H 4H 5H Mnemonic LDA AH US Address 6H 7H 8H 9H AH BH CH DH EH FH DATA FFH FFH FFH 01H OEH 01H OFH FFH FFH FFHanswere fast please question from DIGITAL LOGIC DESIGN TOPIC : Designing Combinational Logic You are designing a water level circuit using 74ALS151 (8 to 1 Multiplexer IC)* When input is 0000 that means tank is empty.* When input is 1111 that means tank is full.* When input is below 5, that means water level is low.* So, make a circuit using 74ALS151 Multiplexer IC that shows a "low water" indicator light(by setting an output L to 1) when the water level drops below level 5.Q1. Show the implementation of 4 bit binary to gray code (shown in below table) converter using either EPROM or PLA. In Gray code only one bit changes at a time. Binary Gray code Decimal equivalent 0000 0000 1 0001 0001 0010 0011 3 0011 0010 4 0100 0110 5 0101 0111 6. 0110 0101 7 0111 0100 8. 1000 1100 1001 1101 10 1010 1111 11 1011 1110 12 1100 1010 13 1101 1011 14 1110 1001 15 1111 1000