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What will be printed by code below? Explain the output. 1 // Program 5(b) 2 3 #include 4 5 int main (void) { 6 int n, m, x, y; 7 m=10; 8 n=m++*2; 9 printf("n: %d", n); printf("\nm: %d", m); 10 11 12 x=10; 13 y=++x*2; 14 printf("\nx: %d", x); printf("\ny: %d", y); 15 16 } What is the final value of t1 and t2? Explain the output. 1 // Program 5(b) 2 3 #include 4 5 int main (void) { 6 int j=2; k=3; 7 double r=24.5, s=3.0, t1, t2; 8 t1*=r+s; t2=r-s*3% (2+j)/k; printf("\nt1: %f", t1); printf("\nt2: %f", t2); }

What will be printed by code below? Explain the output. 1 // Program 5(b) 2 3 #include 4 5 int main (void) { 6 int n, m, x, y; 7 m=10; 8 n=m++*2; 9 printf("n: %d", n); printf("\nm: %d", m); 10 11 12 x=10; 13 y=++x*2; 14 printf("\nx: %d", x); printf("\ny: %d", y); 15 16 } What is the final value of t1 and t2? Explain the output. 1 // Program 5(b) 2 3 #include 4 5 int main (void) { 6 int j=2; k=3; 7 double r=24.5, s=3.0, t1, t2; 8 t1*=r+s; t2=r-s*3% (2+j)/k; printf("\nt1: %f", t1); printf("\nt2: %f", t2); }

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Use c program only please
What will be printed by code below? Explain the output. 1 // Program 5(b) 2 3 #include <stdio.h> 4 5 int main (void) { 6 int n, m, x, y; 7 m=10; 8 n=m++*2; 9 printf("n: %d", n); printf("\nm: %d", m); 10 11 12 x=10; y=++x*2; 13 14 printf("\nx: %d", x); printf("\ny: %d", y); 15 16 } What is the final value of t1 and t2? Explain the output. 1 // Program 5(b) 2 #include <stdio.h> int main (void) { int j=2; k=3; double r=24.5, s=3.0, t1, t2; t1*=r+s; t2=r-s*3% (2+j)/k; printf("\nt1: %f", t1); printf("\nt2: %f", t2); 123 4 56700 8 }
Transcribed Image Text:What will be printed by code below? Explain the output. 1 // Program 5(b) 2 3 #include <stdio.h> 4 5 int main (void) { 6 int n, m, x, y; 7 m=10; 8 n=m++*2; 9 printf("n: %d", n); printf("\nm: %d", m); 10 11 12 x=10; y=++x*2; 13 14 printf("\nx: %d", x); printf("\ny: %d", y); 15 16 } What is the final value of t1 and t2? Explain the output. 1 // Program 5(b) 2 #include <stdio.h> int main (void) { int j=2; k=3; double r=24.5, s=3.0, t1, t2; t1*=r+s; t2=r-s*3% (2+j)/k; printf("\nt1: %f", t1); printf("\nt2: %f", t2); 123 4 56700 8 }
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