What volume of carbon dioxide (in L) will 3.32 g of antacid made of calcium carbonate produce at 37.0 °C and 1.00 atm in the stomach according to the following reaction? CaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

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What volume of carbon dioxide (in L) will 3.32 g of antacid made of calcium carbonate produce at 37.0 °C and 1.00 atm in the stomach according to the following reaction? CaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

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What volume of carbon dioxide (in L) will 3.32 g of antacid made of
calcium carbonate produce at 37.0 °C and 1.00 atm in the stomach
according to the following reaction?
CaCO3 (s) + 2 HCI (aq) → CaCl, (aq) + H2O (I) + CO2 (g)
L
1
3
6.
C
7
8
9
+/-
х 100
+
PAGES
W
4+
Transcribed Image Text:Chrome File Edit View History Bookmarks People Tab Window Help 42% Tue 7:12 PM Chem 101 HW 101 Chem101 + app.101edu.co E Question 23 of 25 Submit What volume of carbon dioxide (in L) will 3.32 g of antacid made of calcium carbonate produce at 37.0 °C and 1.00 atm in the stomach according to the following reaction? CaCO3 (s) + 2 HCI (aq) → CaCl, (aq) + H2O (I) + CO2 (g) L 1 3 6. C 7 8 9 +/- х 100 + PAGES W 4+
Expert Solution
Step 1

Molar mass of CaCO3 = 100.0869 g/mol

Calculation of no. of mol of CaCO3:

n=given massMolar mass=3.32 g100.0869 g/mol=0.03317 mol

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