**Chemical Reaction Problem****Question:**What volume of 0.905 M H₂SO₄ will react with 26.7 mL of 0.554 M NaOH?**Reaction Equation:**\[ \text{H}_2\text{SO}_4(\text{aq}) + 2 \text{NaOH}(\text{aq}) \rightarrow \text{Na}_2\text{SO}_4(\text{aq}) + 2 \text{H}_2\text{O}(\ell) \]In this reaction, sulfuric acid (\(\text{H}_2\text{SO}_4\)) reacts with sodium hydroxide (\(\text{NaOH}\)) to produce sodium sulfate (\(\text{Na}_2\text{SO}_4\)) and water (\(\text{H}_2\text{O}\)). The equation is balanced, showing two moles of NaOH reacting with one mole of \(\text{H}_2\text{SO}_4\).

Neutralization reaction :- The reaction of an acid with a base to form salt and water is known as neutralization reaction For example :- H2SO4 + 2NaOH ------> Na2SO4 + 2H2O Given that, Molarity of H2SO4 (M1) = 0.905 M Volume of NaOH (V2) = 26.7 mL Molarity of NaOH (M2) = 0.554 M Volume of H2SO4 (V1) = ? Given balanced chemical equation is H2SO4 + 2NaOH ------> Na2SO4 + 2H2O In above equation Coefficient of H2SO4 (n1) = 1 Coefficient of NaOH (n2) = 2 Formula :- M1V1n1 = M2V2n2 V1 = M2V2n1n2M1V1 = 0.554 M × 26.7 mL × 12 × 0.905 M V1 = 8.17 mL Answer :- Volume of H2SO4 = 8.17 mL

Answered: What volume of 0.905 M H2SO4 will react…

Science

Chemistry

What volume of 0.905 M H2SO4 will react with 26.7 mL of 0.554 M NAOH? H2SO4(ag) + 2 NAOH(ag) → Na2SO4(ag) + 2 H20(8)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

What volume, in L, of 0.204 M NiCl2 solution is required to produce 69.9 g of precipitate. 3NiCl2(aq) + 2Na3PO4(aq) → Ni3(PO4)2(s) + +6NaCl(aq)
In a double replacement precipitation reaction, KCl reacts with Pb(NO3)2 in a 2:1 mole ratio, respectively. Calculate the volume in mL of a 0.100 mol/L Pb(NO3)2 solution needed to completely react with 40.0 mL of a 0.500 mol/L solution of KCl?
A 10.00 mL vinegar sample is pipetted into an Erlenmeyer flask and titrated with 24.77 mL of 0.575 M NaOH to a permanent endpoint. Calculate the molarity of the acetic acid (HC2H3O2 60.06 g/mol) in the vinegar.
How many mL of 0.450 M of Mg(OH)2 would be needed to neutralize 96.52 grams of HBr? 2HBr(aq) + Mg(OH)2(aq)→MgBr2(aq) + 2H2O(l)
solution after precipitation is complete. 68. The drawings below represent aqueous solutions. Solution A is 2.00 L of a 2.00-M aqueous solution of copper(II) nitrate. Solution B is 2.00 L of a 3.00-M aqueous solution of potas- sium hydroxide. (0) suiro Cu²+ ebro NO3 БО K+ OH™ A B a. Draw a picture of the solution made by mixing solutions A and B together after the precipitation reaction takes place. Make sure this picture shows the correct relative volume compared to solutions A and B, and the correct relative number of ions, along with the correct relative amount of solid formed. b. Determine the concentrations (in M) of all ions left in solution (from part a) and the mass of solid formed.
It took 35.17 mL of 0.5065M NaOH to completely react with a 3.210 g sample of a certain unknown strong monoprotic acid (1 mol of H+ is given off by 1 mol of acid). Calculate the molar mass of the unknown acid.
What volume of water is needed to prepare 500 mL of a 0.25 M Ca(NO3)2 solution from a stock solution of 5.0 M Ca(NO3)2?
What volume (mL) of 0.70 M Sodium hydroxide (NaOH) is needed to neutralize 270 mL of 0.40 M Sulfuricacid (H2SO4)?2 NaOH + H2SO4 Na2SO4 + 2 H2O
7. What volume of 0.120 M NaOH will neutralize half of a 53.8-mL solution of 0.07 M propionic acid, CH3CH₂COOH (a weak monoprotic acid)?
MgCO3(s) + 2 HCl(aq) → MgCl2(aq) + CO2(g) + H2O(l) Calculate the volume of 0.440 M HCl needed for 12.8 g MgCO3 to react completely.
Name the major chemical groups found in organic molecules. Describe the basic structure of each chemical group and outline the chemical properties of the organic molecules in which they occur.
Given the reaction below, if 128.5 mL of 0.860 M Al(NO3)3 is reacted with 246.5 mL of 1.15 M NaOH Al(NO3)3 + 3NaOH → Al(OH)3 + 3NaNO3 Given the information above, Determine the concentration of Al(NO3)3 in mol/L AFTER the reaction has occurred.