What volume of 0.250 M HNO3 (nitric acid) reacts with 44.8 mL of a 0.150 M Na₂CO3 (sodium carbonate) solution? 2 HNO3(aq) + Na₂CO3 (aq) - 2 NaNO3(aq) + H₂O (1) + CO₂ (g)
What volume of 0.250 M HNO3 (nitric acid) reacts with 44.8 mL of a 0.150 M Na₂CO3 (sodium carbonate) solution? 2 HNO3(aq) + Na₂CO3 (aq) - 2 NaNO3(aq) + H₂O (1) + CO₂ (g)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
What volume of 0.250 M HNO₃ (nitric acid) reacts with 44.8 mL of a 0.150 M Na₂CO₃ (sodium carbonate) solution?
**Chemical Equation:**
\[ 2 \, \text{HNO}_3 \, (\text{aq}) + \text{Na}_2\text{CO}_3 \, (\text{aq}) \rightarrow 2 \, \text{NaNO}_3 \, (\text{aq}) + \text{H}_2\text{O} \, (\text{l}) + \text{CO}_2 \, (\text{g}) \]
**Explanation:**
This equation represents the chemical reaction between nitric acid (HNO₃) and sodium carbonate (Na₂CO₃). In this reaction, two moles of aqueous nitric acid react with one mole of aqueous sodium carbonate to produce two moles of aqueous sodium nitrate (NaNO₃), one mole of liquid water (H₂O), and one mole of gaseous carbon dioxide (CO₂).
To solve for the volume of HNO₃ required, use stoichiometry based on the given concentrations and volume of Na₂CO₃.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb0d79c4c-40ce-427b-b4a0-26ffd9f423cd%2F53101874-db53-4534-a75e-f7f691775bec%2Fawkcx4_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
What volume of 0.250 M HNO₃ (nitric acid) reacts with 44.8 mL of a 0.150 M Na₂CO₃ (sodium carbonate) solution?
**Chemical Equation:**
\[ 2 \, \text{HNO}_3 \, (\text{aq}) + \text{Na}_2\text{CO}_3 \, (\text{aq}) \rightarrow 2 \, \text{NaNO}_3 \, (\text{aq}) + \text{H}_2\text{O} \, (\text{l}) + \text{CO}_2 \, (\text{g}) \]
**Explanation:**
This equation represents the chemical reaction between nitric acid (HNO₃) and sodium carbonate (Na₂CO₃). In this reaction, two moles of aqueous nitric acid react with one mole of aqueous sodium carbonate to produce two moles of aqueous sodium nitrate (NaNO₃), one mole of liquid water (H₂O), and one mole of gaseous carbon dioxide (CO₂).
To solve for the volume of HNO₃ required, use stoichiometry based on the given concentrations and volume of Na₂CO₃.
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