Could I have help with the two following questions **Question:**What volume (in mL) of 0.0887 M MgF₂ solution is needed to make 275.0 mL of 0.0224 M MgF₂ solution?**Answer Choices:**- A. 72.3 mL- B. 10.9 mL- C. 69.4 mL- D. 14.4 mL- E. 91.8 mL**Explanation:**This problem involves using the dilution equation:\[ C_1V_1 = C_2V_2 \]Where:- \( C_1 \) is the concentration of the initial solution (0.0887 M)- \( V_1 \) is the volume of the initial solution- \( C_2 \) is the concentration of the final solution (0.0224 M)- \( V_2 \) is the volume of the final solution (275.0 mL)Solve for \( V_1 \) to find the required volume of the initial solution. **Question:**How many grams of NaCl are required to make 250.00 mL of a 3.000 M solution?**Options:**- ○ 14.60 g- ○ 175.3 g- ○ 58.40 g- ○ 43.83 g**Explanation:**To find the amount of grams needed, use the formula:\[ \text{grams of NaCl} = \text{molarity} \times \text{volume in liters} \times \text{molar mass of NaCl} \]- **Molarity (M)** = 3.000 M- **Volume (L)** = 250.00 mL = 0.250 L- **Molar mass of NaCl** ≈ 58.44 g/mol\[ \text{grams of NaCl} = 3.000 \, \text{M} \times 0.250 \, \text{L} \times 58.44 \, \text{g/mol} \]\[ \text{grams of NaCl} = 43.83 \, \text{g} \]Thus, the correct answer is 43.83 g.

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Answered: What volume (in mL) of 0.0887 M MgF₂…

What volume (in mL) of 0.0887 M MgF₂ solution is needed to make 275.0 mL of 0.0224 M MgF₂ solution? O 72.3 mL 10.9 mL 69.4 mL O 14.4 mL 91.8 mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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