Question 8 of 12SubmitWhat volume (in milliliters) of0.160 M HNO, are required toneutralize 70.0 mL of 0.170MКОН?|mL1234C789+/-х 100LO

Acid reacts with base to form salt and water. This reaction is known as neutralization reaction. Here, acid is nitric acid and base is potassium hydroxide. So, one mole of nitric acid reacts with one mole of potassium hydroxide. Molarity of a solution is equal to the number of moles of solute present in one litre of the solution. Write the expression of molarity. M=nV where n is the number of moles of solute and V is the volume of solution. For constant moles, MHNO3VHNO3=MKOHVKOHSubstitute all the values to calculate the volume of nitric acid. VHNO3=0.170 M×70 mL 0.160 M=74.375 mL Therefore, the volume of nitric acid is 74.375 mL.

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What volume (in milliliters) of 0.160 M HNO3 are required to neutralize 70.0 mL of 0.170 M KOH?

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 134AP

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