What volume in L of a 0.724 M Nal solution contains 0.405 mol of Nal ?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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### Educational Exercise: Molarity and Solution Volume Calculation

#### Problem Statement
Determine the volume in liters (L) of a 0.724 M (molar) NaI (sodium iodide) solution required to contain 0.405 moles of NaI.

#### Calculation Interface Overview

1. **Equation Setup:**
   - The interface allows you to set up the calculation using a dimensional analysis format. 
   - You begin with a "STARTING AMOUNT" section where you can input values.

2. **Factor and Calculation Structure:**
   - The calculation process involves multiplying the starting amount by a conversion factor in parentheses to find the answer.
   - The structure for inputs accommodates assigning known values, such as molarity and moles, to solve for volume.

3. **Input Fields and Buttons:**
   - Numerical inputs available include 0.405, 0.724, and others.
   - Buttons specify units or constants, like "mol NaI," "g NaI/mol," and "M NaI" to help guide correct factor placement.
   - The section labeled "ANSWER" presents the calculated result.
   - A "RESET" button allows clearing inputs for a new attempt.

#### Steps for Solving:
- Use the given molarity of the solution (0.724 M) and the moles of NaI (0.405 moles) to calculate the necessary volume in liters.
- Apply the formula:
  \[
  \text{Volume (L)} = \frac{\text{moles of solute}}{\text{molarity (M)}}
  \]
  \[
  \text{Volume (L)} = \frac{0.405 \, \text{mol}}{0.724 \, \text{M}}
  \]

This exercise applies basic concepts of solution chemistry, illustrating how to manipulate units for calculations involving molarity and volume.
Transcribed Image Text:### Educational Exercise: Molarity and Solution Volume Calculation #### Problem Statement Determine the volume in liters (L) of a 0.724 M (molar) NaI (sodium iodide) solution required to contain 0.405 moles of NaI. #### Calculation Interface Overview 1. **Equation Setup:** - The interface allows you to set up the calculation using a dimensional analysis format. - You begin with a "STARTING AMOUNT" section where you can input values. 2. **Factor and Calculation Structure:** - The calculation process involves multiplying the starting amount by a conversion factor in parentheses to find the answer. - The structure for inputs accommodates assigning known values, such as molarity and moles, to solve for volume. 3. **Input Fields and Buttons:** - Numerical inputs available include 0.405, 0.724, and others. - Buttons specify units or constants, like "mol NaI," "g NaI/mol," and "M NaI" to help guide correct factor placement. - The section labeled "ANSWER" presents the calculated result. - A "RESET" button allows clearing inputs for a new attempt. #### Steps for Solving: - Use the given molarity of the solution (0.724 M) and the moles of NaI (0.405 moles) to calculate the necessary volume in liters. - Apply the formula: \[ \text{Volume (L)} = \frac{\text{moles of solute}}{\text{molarity (M)}} \] \[ \text{Volume (L)} = \frac{0.405 \, \text{mol}}{0.724 \, \text{M}} \] This exercise applies basic concepts of solution chemistry, illustrating how to manipulate units for calculations involving molarity and volume.
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