What values are left in the variables after executing the following C code:unsigned char u ;signed char s ;u = (unsigned char) -128 ;(signed char) +128 ;S =IT (0)al (

1) We have C code in question which does below steps It declare a unsigned char variable u It…

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Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Question

What values are left in the variables after executing the following C code:
unsigned char u ;
signed char s ;
u = (unsigned char) -128 ;
(signed char) +128 ;
S =
IT (0)
al (

Expert Solution

Explanation

1) We have C code in question which does below steps

It declare a unsigned char variable u
It declare a singed char variables s;
It assign value to variable u
- assign value is negative but type casted to unsigned char
It assign value to variable s
- assign a positive value but type casted to signed char

2) Type casting is basically a process in C in which we change a variable belonging to one data type to another one.

An unsigned type can only represent positive values (and zero) where as a signed type can represent both positive and negative values (and zero).
In the case of a 8-bit char this means that an unsigned char variable can hold a value in the range 0 to 255 while a signed char has the range -128 to 127.

3) type casting convert -128 value to unsigned char, so it is converted into a positive number where negative signed is ignored. So value of u becomes 128