What steps will we take if the data bus is only 16 bits wide but our instruction is 64 bits long? What outcomes can we anticipate if the data bus is only 16 bits wide but our instruction is only 8 bits long?

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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**Handling Data Bus Width and Instruction Length in Computing Systems**

*Question:*
What steps will we take if the data bus is only 16 bits wide but our instruction is 64 bits long? What outcomes can we anticipate if the data bus is only 16 bits wide but our instruction is only 8 bits long?

*Explanation:*
### Scenario 1: 16-bit Data Bus, 64-bit Instruction
1. **Segmentation of Instruction**: The 64-bit instruction will need to be segmented into smaller parts because the data bus can only handle 16 bits at a time. This means the instruction will be divided into four 16-bit segments.
2. **Multiple Data Transfers**: The system must transfer each 16-bit segment sequentially. This requires four separate data transfer cycles to send the complete 64-bit instruction.
3. **Increased Processing Time**: The overall processing time will increase due to the multiple cycles needed for transferring the complete instruction. This can lead to a slowdown in system performance.

### Scenario 2: 16-bit Data Bus, 8-bit Instruction
1. **Single Transfer Cycle**: Since the data bus is 16 bits wide and the instruction is only 8 bits long, the entire instruction can be transferred in a single cycle. 
2. **Unused Data Bus Capacity**: The remaining 8 bits of the data bus will be unused during this transfer. However, this does not negatively impact the transfer speed since only one cycle is required.
3. **Efficient Utilization**: The system will experience efficient instruction transfer without delays, ensuring minimal impact on performance.

This understanding is crucial for optimizing computer architecture and ensuring efficient data processing.
Transcribed Image Text:**Handling Data Bus Width and Instruction Length in Computing Systems** *Question:* What steps will we take if the data bus is only 16 bits wide but our instruction is 64 bits long? What outcomes can we anticipate if the data bus is only 16 bits wide but our instruction is only 8 bits long? *Explanation:* ### Scenario 1: 16-bit Data Bus, 64-bit Instruction 1. **Segmentation of Instruction**: The 64-bit instruction will need to be segmented into smaller parts because the data bus can only handle 16 bits at a time. This means the instruction will be divided into four 16-bit segments. 2. **Multiple Data Transfers**: The system must transfer each 16-bit segment sequentially. This requires four separate data transfer cycles to send the complete 64-bit instruction. 3. **Increased Processing Time**: The overall processing time will increase due to the multiple cycles needed for transferring the complete instruction. This can lead to a slowdown in system performance. ### Scenario 2: 16-bit Data Bus, 8-bit Instruction 1. **Single Transfer Cycle**: Since the data bus is 16 bits wide and the instruction is only 8 bits long, the entire instruction can be transferred in a single cycle. 2. **Unused Data Bus Capacity**: The remaining 8 bits of the data bus will be unused during this transfer. However, this does not negatively impact the transfer speed since only one cycle is required. 3. **Efficient Utilization**: The system will experience efficient instruction transfer without delays, ensuring minimal impact on performance. This understanding is crucial for optimizing computer architecture and ensuring efficient data processing.
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