What should the dimensions of the box be in order to minimize the surface area?

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter5: Factoring Polynomials
Section5.13: Using Factoring To Solve Problems
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I am designing a box for my cat. The box will be a rectangular solid with no top and a length that is twice its width. The box will have a volume of 36ft^3. What should the dimensions of the box be in order to minimize the surface area?

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Let,Breadth of the box = b = xLength of the box = l = 2b = 2x        (according to question)Height of the box = hVolume of the box = l×b×hVolume of the box given = 36 ft3Then,l×b×h = 362x×x×h = 362x2×h = 36h = 362x2h = 18x2           ......................(1)Surface area of the solid S = 2lb+bh+hl-lb              subtracting lb because box is open from topS = 22x×x+x×h+h×2x-2x×xS = 22x2+xh+2hx-2x2S = 2(2x2+3hx)-2x2S = 4x2+6hx-2x2S = 2x2+6hxUsing equation (1) -S = 2x2+618x2xS = 2x2+108x           ...............(2)

 

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