**Question:**What should be the direction and magnitude of the vertical electric field that will balance the weight of a plastic sphere with the charge $ Q = +1.5 \, \text{nC} $ and mass $ m = 1.8 \, \text{g} $?**Options:**1. $ 3.2 \times 10^5 \, \text{N/C} $ positive y-direction2. $ 1.2 \times 10^6 \, \text{N/C} $ in +y-direction3. $ 1.2 \times 10^6 \, \text{N/C} $ in negative y-direction4. $ 3.2 \times 10^5 \, \text{N/C} $ in negative y-direction

Answered: What should be the direction and…

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.7CQ: A person is placed in a large, hollow, metallic sphere that is insulated from ground, (a) If a large...

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This is a question regarding the force on a charged particle due to an electric field.

The force on a charged particle due to an electric field is given by the formula:
$\vec{F_{e}} = q \vec{E} . . . (i)$
where,
$\vec{F_{e}}$ is the force,
q is the charge on the particle and
$\vec{E}$ is the electric field.

The weight of a body is given by the formula:
$\vec{F_{g}} = m \vec{g} . . . (i i)$
where,
$\vec{F_{g}}$ is the weight of the body,
m is the mass of the body and
$\vec{g}$ is the acceleration due to gravity.

The acceleration due to gravity always acts vertically downwards towards the center of the Earth and its value is:
$g = 9.8 {m/s}^{2}$

The values given in the question are:
The mass of the body is: $m = 1.8 g = 1.8 \times 10^{- 3} kg$
The charge of the body is: $q = + 1.5 nC = + 1.5 \times 10^{- 9} C$

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