Homework Help is Here – Start Your Trial Now!
Science
Chemistry
What quantity in moles of phosphorus atoms do you have if you have 4.30 x 1022 atoms of phosphorus. (The mass of one mole of phosphorus is 30.97 g.) 4

What quantity in moles of phosphorus atoms do you have if you have 4.30 x 1022 atoms of phosphorus. (The mass of one mole of phosphorus is 30.97 g.) 4

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question
100%
**Question:** What quantity in moles of phosphorus atoms do you have if you have \(4.30 \times 10^{22}\) atoms of phosphorus? (The mass of one mole of phosphorus is 30.97 g.) **Explanation:** To find the quantity in moles, use Avogadro's number, which is \(6.022 \times 10^{23}\) atoms/mole. Divide the number of atoms by Avogadro’s number: \[ \text{Moles of phosphorus} = \frac{4.30 \times 10^{22} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \] This calculation will give the quantity of phosphorus in moles. The mass information provided is additional and not needed for finding moles, but it can be used to calculate the weight if needed.
Transcribed Image Text:**Question:** What quantity in moles of phosphorus atoms do you have if you have \(4.30 \times 10^{22}\) atoms of phosphorus? (The mass of one mole of phosphorus is 30.97 g.) **Explanation:** To find the quantity in moles, use Avogadro's number, which is \(6.022 \times 10^{23}\) atoms/mole. Divide the number of atoms by Avogadro’s number: \[ \text{Moles of phosphorus} = \frac{4.30 \times 10^{22} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \] This calculation will give the quantity of phosphorus in moles. The mass information provided is additional and not needed for finding moles, but it can be used to calculate the weight if needed.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Mole Concept
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS