Answered: What potential difference must be… | bartleby

Related questions

Question

What potential difference must be applied to stop the fastest
photoelectrons emitted by a surface when electromagnetic radiation of
frequency 1.5 * 10 ^ 15 * H * z is allowed to fall on it. The work function of
the surface is 5 ev.

Expert Solution

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

(a) A photoelectric experiment is performed where green light with a wavelength of 546.1 nm is shined on a metal plate, creating a photocurrent from it to a collector plate. When the potential difference between the metal plate and the collector is increased to a magnitude of 0.686 V, the photocurrent goes to zero—in other words, this is the stopping potential. What is the work function (in eV) for this metal? answer in eV (b) The experiment is performed again with the same metal, but now red light with a wavelength 650.0 nm is shined on it. What is the new stopping potential (in V) in this case? answer in V
The work function of a material is 6 eV what is the potential difference that is required to stop the fastest photoelectrons emitted by a surface when electromagnetic radiation of frequency 4.5 * 10 ^ 15 * Hz is allowed to fall on it.
The work function of caesium metal is 2.14 eV. When light of frequency 6 x 1014 Hz is incident on the metal surface, photoemission of electrons occurs. What is the maximum kinetic energy of the emitted electrons,
Light with a frequency of (1.99x10^15) Hz hits a metal with a work function of (4.200x10^0) eV. Determine the maximum velocity of photoelectrons generated by this setup.
An experiment is performed where light of different frequencies is shined on an aluminum plate. The work function for aluminum is 4.08 eV. (a) What is the lowest frequency (the "cutoff" frequency, in Hz) of light incident on aluminum, below which no photoelectrons will be emitted from its surface? Hz (b) What is the longest wavelength (the "cutoff" wavelength, in nm) of light incident on aluminum, above which no photoelectrons will be emitted from its surface? nm (c) Photons of energy 5.75 eV are incident on the aluminum plate. What is the maximum kinetic energy (in eV) of the ejected photoelectrons? ev
A certain metal has a work function of 4.55 eV. For this metal, find (a) the minimum frequency that light must have to produce photoelectrons and (b) the frequency that light must have to produce photoelectrons with maximum kinetic energy 1.53 eV.
Considering the photoelectric effect, if a liberated photoelectron has a maximum kinetic energy of 0.236 eV when light with a wavelength of 439 nm is being used, what is the work function of the material measured in eV?