What percentage of the incoming solar radiation (341.3 W/m2) gets reflected directly back to space by the atmosphere alone?
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What percentage of the incoming solar radiation (341.3 W/m2) gets reflected directly back to space by the atmosphere alone?
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- The air quality index in Beijing last year recorded average ozone (O3) levels of 110 ppb (on a mol basis). Does this exceed Canada's acceptable 24 hour National Ambient Air Quality Objective (NAAQO) of 50 micrograms/M3? Assume the average molar mass of air is 29.0 g/mol and its density is 1.225 kg/M3.Consider a 260-m2 black roof on a night when the roof’s temperature is 27.5°C and the surrounding temperature is 12.5°C. The emissivity of the roof is 0.900. At what net rate does heat radiate, in kilowatts, from the roof?A person is standing outdoors in the shade where the temperature is 33 °C. The surface area of the hair (assumed to be flat) is 170 cm2 and its emissivity is 0.85. What would be the radiant energy absorbed per second by the same person if he were bald and the emissivity of his head were 0.65?
- Suppose a skier standing in the shade is completely clothed in white (head to foot, including a ski mask), with clothes that have an emissivity of 0.200 and a surface temperature of 12.5°C. The surroundings are at -15°C and her surface area is 1.55 m2. a. Find the net rate of heat transfer, in watts, via radiation from the skier.The recommended daily caloric intake is 2000 calories (8,400,000J). This is because this is the same value for how much the average body loses to heat and work in a typical day (your change in energy is zero because you take in the same amount of energy you lose). A) If you lose a total of 8,400,000J (Qout+W=total lost), but consume 1200 calories of food (5,000,000J), what would your change in energy be? B) Assuming your change in energy is negative (hint-it should be), where does your body get the extra energy to maintain it's temperature?type answer