**Title: Understanding Confidence Intervals in Healthcare Statistics****Introduction:**In assessing the percentage of hospitals that provide at least some charity care, statistical data from a random sample of hospital reports from eastern states is utilized. The following percentages represent hospitals providing some level of charity care:**Data:** 57.3, 55.5, 53.3, 65.5, 59.0, 64.7, 70.1, 64.7, 53.5, 78.2**Assumption:** The data distribution is approximately normal, allowing for standard statistical computations.**Tasks:****(a) Calculate the Sample Mean and Standard Deviation**To determine the average percentage of hospitals that offer charity care and understand the variability within the data, use a calculator to compute:- **Sample Mean ($\bar{x}$)**: This provides the average percentage.- **Sample Standard Deviation ($s$)**: This indicates the amount of variation from the mean.**(b) Determine the 90% Confidence Interval**Establish a range in which the true population mean is likely to fall, with a confidence level of 90%. This involves calculating:- **Lower Limit**: The lower boundary of the confidence interval.- **Upper Limit**: The upper boundary of the confidence interval.**Conclusion:**These calculations provide insights into the typical extent of charity care offerings among hospitals in the studied region, aiding in healthcare policy and planning. Understanding these statistics is vital for grasping how charity care is distributed and identifying areas for potential improvement.*Note: Round all answers to one decimal place for uniformity and ease of interpretation.*

From the provided information, Sample size (n) = 10

Answered: What percentage of hospitals provide at…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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