What percent of a standard normal distribution N(u = 0; o = 1) is found in each region? Be sure to draw a graph. Write your answer as a percent rounded to the nearest tenth. a) The region Z < - 1.35 is approximately % of the area under the standard normal curve. b) The region Z > 1.48 is approximately % of the area under the standard normal curve. c) The region - 0.4 < Z < 1.5 is approximately % of the area under the standard normal curve.
What percent of a standard normal distribution N(u = 0; o = 1) is found in each region? Be sure to draw a graph. Write your answer as a percent rounded to the nearest tenth. a) The region Z < - 1.35 is approximately % of the area under the standard normal curve. b) The region Z > 1.48 is approximately % of the area under the standard normal curve. c) The region - 0.4 < Z < 1.5 is approximately % of the area under the standard normal curve.
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![What percent of a standard normal distribution N(u = 0; o = 1) is found in each region? Be sure to draw a
graph. Write your answer as a percent rounded to the nearest tenth.
%3D
a) The region Z <
– 1.35 is approximately
% of the area under the standard normal curve.
b) The region Z > 1.48 is approximately
% of the area under the standard normal curve.
c) The region – 0.4 < Z < 1.5 is approximately
% of the area under the standard normal curve.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F82db88bb-f012-41c2-80d1-18aa8944e818%2F88403296-1d87-424a-a794-da25b9160626%2Fyq384e4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:What percent of a standard normal distribution N(u = 0; o = 1) is found in each region? Be sure to draw a
graph. Write your answer as a percent rounded to the nearest tenth.
%3D
a) The region Z <
– 1.35 is approximately
% of the area under the standard normal curve.
b) The region Z > 1.48 is approximately
% of the area under the standard normal curve.
c) The region – 0.4 < Z < 1.5 is approximately
% of the area under the standard normal curve.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given information:
a) The region under is computed as:
Therefore, the region is approximately 8.85% of the area under the standard normal curve.
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