What olume of 17.1 M glacial acetic acid (HC2H3O2) must be added to 100.0 mL of 1.25 M KOH to form a buffer with a pH of 4.20? Ka (HC2H3O2) = 1.8 x 10-5 %3D

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What olume of 17.1 M glacial acetic acid (HC2H3O2) must be added to 100.0 mL of 1.25 M
KOH to form a buffer with a pH of 4.20?
Ka (HC2H3O2) = 1.8 x 10-5
%3D
Transcribed Image Text:What olume of 17.1 M glacial acetic acid (HC2H3O2) must be added to 100.0 mL of 1.25 M KOH to form a buffer with a pH of 4.20? Ka (HC2H3O2) = 1.8 x 10-5 %3D
Expert Solution
Step 1

Given,

Molarity of glacial acetic acid=1.71M

Volume of KOH=100mL

Molarity of KOH=1.25M

pH of buffer=4.20

The reaction between acetic acid and potassium hydroxide is given below.

Chemistry homework question answer, step 1, image 1

The number of moles of NaOH present in 100mL of 1.25M KOH can be calculated as shown below.

Chemistry homework question answer, step 1, image 2

 

Step 2

Assume that x moles of acetic acid is added to 0.125moles of KOH and construct the ICE table as follows:

Chemistry homework question answer, step 2, image 1

 So, the equilibrium concentrations of acid and conjugate base are:

Chemistry homework question answer, step 2, image 2

Here, Vtotal  is the total volume of the buffer solution.

The value of pKa for acetic acid can be calculated as shown below.

Chemistry homework question answer, step 2, image 3

The pH of the buffer is 4.2

Using Henderson-Hasselbach equation, calculate x follows:

Chemistry homework question answer, step 2, image 4

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