What new element is formed when 40K decays by B- emission? Is the new element formed likely to be stable? Why or why not? New element formed: OA. Likely to be stable B. Likely to be unstable
What new element is formed when 40K decays by B- emission? Is the new element formed likely to be stable? Why or why not? New element formed: OA. Likely to be stable B. Likely to be unstable
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Decay of Potassium-40 (^(40)K):**
**Question:**
What new element is formed when \(^{40}\text{K}\) decays by β⁻ emission? Is the new element formed likely to be stable? Why or why not?
**New element formed:**
[Text box for user's response]
**Options:**
- \(\bigcirc\) A. Likely to be stable
- \(\bigcirc\) B. Likely to be unstable
---
**Explanation:**
When Potassium-40 (\(^{40}\text{K}\)) undergoes beta (β⁻)-decay, it emits a beta particle (an electron) and forms a new element in the process. This decay process increases the atomic number of the original element by one while keeping the atomic mass number the same. The resulting element from the beta decay of \(^{40}\text{K}\) is Calcium-40 (\(^{40}\text{Ca}\)).
**Beta Decay Equation:**
\[
^{40}_{19}\text{K} \rightarrow \,^{40}_{20}\text{Ca} + \beta^- + \overline{\nu}_e
\]
- \(^{40}_{19}\text{K}\) is Potassium-40.
- \(^{40}_{20}\text{Ca}\) is Calcium-40.
- \(\beta^-\) is the emitted beta particle (electron).
- \(\overline{\nu}_e\) is the emitted antineutrino.
**Stability Analysis:**
To determine whether the newly formed Calcium-40 is stable or not, we consider its position on the nuclear stability chart. Calcium-40 is a stable isotope with 20 protons and 20 neutrons, making it a doubly magic nucleus, which are particularly stable configurations in nuclear physics.
**Answer:**
- \(\bigcirc\) A. Likely to be stable
Therefore, the new element (Calcium-40) formed after the β⁻-decay of Potassium-40 is likely to be stable.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7ffebb09-73dd-4031-aaac-f04b5d70d3fe%2F2b658b7b-cb04-4251-8dac-cda8d7373d46%2Fnawoah_processed.png&w=3840&q=75)
Transcribed Image Text:**Decay of Potassium-40 (^(40)K):**
**Question:**
What new element is formed when \(^{40}\text{K}\) decays by β⁻ emission? Is the new element formed likely to be stable? Why or why not?
**New element formed:**
[Text box for user's response]
**Options:**
- \(\bigcirc\) A. Likely to be stable
- \(\bigcirc\) B. Likely to be unstable
---
**Explanation:**
When Potassium-40 (\(^{40}\text{K}\)) undergoes beta (β⁻)-decay, it emits a beta particle (an electron) and forms a new element in the process. This decay process increases the atomic number of the original element by one while keeping the atomic mass number the same. The resulting element from the beta decay of \(^{40}\text{K}\) is Calcium-40 (\(^{40}\text{Ca}\)).
**Beta Decay Equation:**
\[
^{40}_{19}\text{K} \rightarrow \,^{40}_{20}\text{Ca} + \beta^- + \overline{\nu}_e
\]
- \(^{40}_{19}\text{K}\) is Potassium-40.
- \(^{40}_{20}\text{Ca}\) is Calcium-40.
- \(\beta^-\) is the emitted beta particle (electron).
- \(\overline{\nu}_e\) is the emitted antineutrino.
**Stability Analysis:**
To determine whether the newly formed Calcium-40 is stable or not, we consider its position on the nuclear stability chart. Calcium-40 is a stable isotope with 20 protons and 20 neutrons, making it a doubly magic nucleus, which are particularly stable configurations in nuclear physics.
**Answer:**
- \(\bigcirc\) A. Likely to be stable
Therefore, the new element (Calcium-40) formed after the β⁻-decay of Potassium-40 is likely to be stable.
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