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What NaCl concentration results when 304 mL of a 0.600 M NaCl solution is mixed with 467 mL of a 0.260 M NaCl solution? concentration: M

What NaCl concentration results when 304 mL of a 0.600 M NaCl solution is mixed with 467 mL of a 0.260 M NaCl solution? concentration: M

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What NaCI concentration results when 304 mL of a 0.600 M NaCI solution is mixed with 467 mL of a 0.260 M NaCI solution?
### Problem Statement What NaCl concentration results when 304 mL of a 0.600 M NaCl solution is mixed with 467 mL of a 0.260 M NaCl solution? ### Solution To find the resulting concentration of the mixed NaCl solution, follow these steps: 1. **Calculate the total moles of NaCl** in each solution before mixing: - Solution 1: \( \text{Volume} = 0.304 \, \text{L}, \, \text{Concentration} = 0.600 \, \text{M} \) \[ \text{Moles of NaCl in Solution 1} = \text{Volume} \times \text{Concentration} = 0.304 \times 0.600 = 0.1824 \, \text{moles} \] - Solution 2: \( \text{Volume} = 0.467 \, \text{L}, \, \text{Concentration} = 0.260 \, \text{M} \) \[ \text{Moles of NaCl in Solution 2} = \text{Volume} \times \text{Concentration} = 0.467 \times 0.260 = 0.12142 \, \text{moles} \] 2. **Calculate the total moles of NaCl** after mixing: \[ \text{Total Moles of NaCl} = 0.1824 + 0.12142 = 0.30382 \, \text{moles} \] 3. **Calculate the total volume** of the mixed solution: \[ \text{Total Volume} = 0.304 \, \text{L} + 0.467 \, \text{L} = 0.771 \, \text{L} \] 4. **Determine the concentration** of the mixed solution: \[ \text{Resulting Concentration} = \frac{\text{Total Moles of NaCl}}{\text{Total Volume}} = \frac{0.30382}{0.771} \approx 0.394 \, \text{M} \] ### Final Answer - **Concentration**: \(\approx 0.394 \,
Transcribed Image Text:### Problem Statement What NaCl concentration results when 304 mL of a 0.600 M NaCl solution is mixed with 467 mL of a 0.260 M NaCl solution? ### Solution To find the resulting concentration of the mixed NaCl solution, follow these steps: 1. **Calculate the total moles of NaCl** in each solution before mixing: - Solution 1: \( \text{Volume} = 0.304 \, \text{L}, \, \text{Concentration} = 0.600 \, \text{M} \) \[ \text{Moles of NaCl in Solution 1} = \text{Volume} \times \text{Concentration} = 0.304 \times 0.600 = 0.1824 \, \text{moles} \] - Solution 2: \( \text{Volume} = 0.467 \, \text{L}, \, \text{Concentration} = 0.260 \, \text{M} \) \[ \text{Moles of NaCl in Solution 2} = \text{Volume} \times \text{Concentration} = 0.467 \times 0.260 = 0.12142 \, \text{moles} \] 2. **Calculate the total moles of NaCl** after mixing: \[ \text{Total Moles of NaCl} = 0.1824 + 0.12142 = 0.30382 \, \text{moles} \] 3. **Calculate the total volume** of the mixed solution: \[ \text{Total Volume} = 0.304 \, \text{L} + 0.467 \, \text{L} = 0.771 \, \text{L} \] 4. **Determine the concentration** of the mixed solution: \[ \text{Resulting Concentration} = \frac{\text{Total Moles of NaCl}}{\text{Total Volume}} = \frac{0.30382}{0.771} \approx 0.394 \, \text{M} \] ### Final Answer - **Concentration**: \(\approx 0.394 \,
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