What must be the divisor of 9x + 6x – 35 to get 3x - 5? В. Зх-7 C. -3x + 7 A. 3x + 7 D. -3x - 7
What must be the divisor of 9x + 6x – 35 to get 3x - 5? В. Зх-7 C. -3x + 7 A. 3x + 7 D. -3x - 7
ChapterP: Prerequisites
SectionP.3: Polynomials And Special Products
Problem 4ECP: Multiply x2+2x+3 by x22x+3 using a vertical arrangement.
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![What must be the divisor of 9x² + 6x – 35 to get 3x – 5?
В. Зх-7
С. -Зх +7
А. Зх +7
D. -3x – 7](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F168d0bc8-0db6-4656-bb0a-57133a13de17%2F6eb46cde-cd58-4ad6-b126-925abf4d274e%2Fzb37ejs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:What must be the divisor of 9x² + 6x – 35 to get 3x – 5?
В. Зх-7
С. -Зх +7
А. Зх +7
D. -3x – 7
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