What must be the divisor of 9x + 6x – 35 to get 3x - 5? В. Зх-7 C. -3x + 7 A. 3x + 7 D. -3x - 7
What must be the divisor of 9x + 6x – 35 to get 3x - 5? В. Зх-7 C. -3x + 7 A. 3x + 7 D. -3x - 7
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Transcribed Image Text:What must be the divisor of 9x² + 6x – 35 to get 3x – 5?
В. Зх-7
С. -Зх +7
А. Зх +7
D. -3x – 7
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