What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO3) 2 reacts with 39.5 mL of 0.500 M NaOH in the following chemical reaction? Cu(NO3)2 (aq) +2 NaOH(aq) → Cu (OH)2(s) + 2 NaNO3(aq)

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Chapter4: Chemical Reactions
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6:36 PM Mon Oct 9
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What mass of precipitate (in g) is formed
when 20.5 mL of 0.500 M Cu(NO3)2 reacts
with 39.5 mL of 0.500 M NaOH in the
following chemical reaction?
Cu(NO3)2(aq) + 2 NaOH(aq) → Cu(OH)₂ (s)
+ 2 NaNO3(aq)
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Question 9 of 14
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Transcribed Image Text:ab 6:36 PM Mon Oct 9 Tap here or pull up for additional resources What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO3)2 reacts with 39.5 mL of 0.500 M NaOH in the following chemical reaction? Cu(NO3)2(aq) + 2 NaOH(aq) → Cu(OH)₂ (s) + 2 NaNO3(aq) ! 1 Q @ 2 W # 3 E $ 4 R or do % 5 T ^ 6 ... Question 9 of 14 Y & 7 U 8 ( 9 1 1 4 7 +/- ) 0 O
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