What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO3)2 reacts with 32.5 mL of 0.300 M NaOH in the following chemical reaction? Ni(NO3)2(aq) + 2 NaOH(aq) → Ni(OH)₂(s) + 2 NaNO3(aq)

Q: 0.7532 g of copper turnings (molar mass: 63.546 g∙mol–1) are reacted with excess nitric acid.…

A: Disclaimer: In order to obtain copper sulfate the acid used in excess should be sulfuric acid and…

Q: What mass of precipitate (in g) is formed when 72.8 mL of 0.500 M FeCl₃ reacts with excess AgNO₃ in…

A: From the reaction it is clear that 1 mole FeCl3 reacts with 3 moles AgNO3 to give 3 moles AgCl.…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO3)2 reacts with 16.0 mL of…

A:

Q: What mass of precipitate (in g) is formed when 82.4 mL of 0.500 M AICI reacts with excess AgNO3 in…

A:

Q: How many moles of precipitate will be formed when 85.3 mL of 0.350 M AgNO₃ is reacted with excess…

A: Given data,Molarity of AgNO3=0.350MVolume of AgNO3=85.3mL=0.0853L

Q: A 2.88 g sample of iron ore is transformed to a solution of iron(II) sulfate, FeSO4. This solution…

A:

Q: How many moles of precipitate will be formed when 70.0 mL of 2.00 M NaBr is reacted with 300.0 mL of…

A: The balanced chemical reaction:2NaBr(aq) + Pb(NO3)2(aq) → PbBr2(s) + 2NaNO3(aq)The volume of 2.00 M…

Q: What mass of precipitate (in g) is formed when 250.0 mL of 0.200 M CoCl₂ is mixed with excess KOH in…

A: The balanced equation is given as;   CoCl2(aq) + 2 KOH (aq)→Co(OH)2(s)+2KCl(aq) From the question,…

Q: What quantity in moles of precipitate will be formed when 73.7 mL of 0.150 M AgNO₃ is reacted with…

A:

Q: you begin with 78.2 mL of 0.725 M KCl(aq) solution and mix it with 67 mL of 0.721 M Pb(NO3)2(aq) ,…

A: Given-> Volume of KCl= 78.2 ml Molarity of KCl = 0.725 M Volume of Pb(NO3)2(aq) = 67 ml Molarity…

Q: AgNO₃(aq) → 3 AgCl(s) + Fe(NO₃)₃(aq)

A: This can be solved by balancing the equation.required solution is given below

Q: If 19.5 g of NaOH is added to 0.800 L of 1.00 M Zn(NO₃)₂, how many grams of Zn(OH)₂ will be formed…

A: Given, Mass of NaOH = 19.5 g            Molarity of Zn(NO₃)₂ = 1.00 M            Volume of Zn(NO₃)₂…

Q: What quantity in moles of precipitate will be formed when 168.0 mL of 0.350 M NaCl is reacted with…

A:

Q: What volume of 0.250 M Na3PO4 is required to precipitate all the lead(II) ions from 190.0 mL of…

A: Molarity is defined as number of mole of solute divide by volume of solution in liter

Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M K₃PO₄ reacts with 47.0 mL of 0.200…

A:

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 23.0 mL of…

A: Number of moles of substance=Concentration of substance x Volume of substanceFor…

Q: If 29.0 g of NaOH is added to 0.700 L of 1.00 M Co(NO₃)₂, how many grams of Co(OH)₂ will be formed…

A: Since ,         no of moles of CoNO32= Concentration of solution x…

Q: Concentration of calcium in a sample may be determined by precipitation using the chromate ion,…

A:

Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M K₃PO₄ reacts with 64.0 mL of 0.200…

A: When stoichiometric coefficient results in the equal number of atoms of each element on both the…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 31.0 mL of…

A: ZnNO32+2 NaOH→ZnOH2 s+2 NaNO3 aqStength of ZnNO32=20.5x0.700 M1000=0.0143Stength of NaOH=310x0.700…

Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Li₃PO₄ reacts with 44.0 mL of…

A: The balanced reaction given is, => Li₃PO₄(aq) + Cr(NO₃)₃(aq) → CrPO₄(s) + 3 LiNO₃(aq) Given :…

Q: How many moles of precipitate will be formed when 70.2 mL of 0.150 M AgNO₃ is reacted with excess…

A:

Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Na PO reacts with 62.5 mL of 0.200…

A: Since, Molarity is the number of moles of solute dissolve in one litre of the solution. Thus,

Q: what mass precipitate (in g) is formed when 20.5 mL of0.800 M Co(NO3)2 reacts with 29.0 mL of 0.800…

A:

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO₃)₂ reacts with 22.5 mL of…

A: According law of mass action, the same amount of mass involved in the reaction is formed as a…

Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M K₃PO₄ reacts with 59.0 mL of 0.200…

A: With data's given Initially moles of K3PO4 and Crcl3 is found and from that limiting reagent is…

Q: Chemistry 1. Calculate the pH of the following two buffer solutions: a. CH3COONa 3.0 M / CH3COOH 3.0…

A: Given data: The solution (a) has = CH3COONa 3.0 M / CH3COOH 3.0 M The solution (b) has = CH3COONa…

Q: What is the molarity of a solution of HCl if 5.50 mL of the HCl solution is titrated with 30.6 mL of…

A: Since as per the reaction, the moles of HCl reacting = moles of NaOH taken  because 1 mole of HCl is…

Q: A 20.0 mL sample of an unknown HClO4HClO4 solution requires 45.3 mL of 0.105 MM NaOHNaOH for…

A: In titration reactions, the moles of the reactants are equated as per the reaction by using the…

Q: How many moles of precipitate will be formed when 108.5 mL of 0.200 M NaBr is reacted with excess…

A: Given,Volume of NaBr = 108.5 mL = 0.1085 L       (1 mL =0.001 L)Molarity of NaBr = 0.200 M = 0.2…

Q: Concentration of calcium in a sample may be determined by precipitation using the chromate ion, Cro…

A:

Q: If 28.0 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₃)₂, how many grams of Ni(OH)₂ will be formed…

A: In the reaction ; 2 NaOH(aq) + Ni(NO₃)₂(aq) → Ni(OH)₂ (s) + 2 NaNO₃ (aq) So, we can conclude that 2…

Q: What is the mass in grams of precipitate formed when 86 mL of 0.50 M FeCl3 reacts with excess AgNO3…

A:

Q: If 33.0 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₂), how many grams of Ni(OH)₂ will be formed in…

A: we have to calculate the mass of precipitate formed in the given reaction

Q: How many moles of precipitate will be formed when 69.3 mL of 0.350 M AgNO₃ is reacted with excess…

A: Given the chemical reaction as follows,2 AgNO3(aq) + MgI2(aq) → 2 AgI(s) + Mg(NO3)2(aq)we are asked…

Q: . Which statements about entropy, enthalpy, and energy are correct for the reaction below? C5H12(g)…

A:

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.400 M Mn(NO₃)₂ reacts with 32.0 mL of…

A:

Q: What is the mass in grams of precipitate formed when 45.5 mL of 0.300 M Na₃PO₄ reacts with 40.0 mL…

A: Balanced chemical equation: Na₃PO₄ (aq) + Cr(NO₃)₃ (aq) → CrPO₄ (s) + 3 NaNO₃ (aq) Number of moles =…

Q: A titration experiment required 16.64 mL of NaOH, which had a concentration of 0.135 M, to reach the…

A:

Q: If 32.5 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₃)₂, how many grams of Ni(OH)₂ will be formed…

A: The reaction considered is, 2 NaOH(aq)+Ni(NO3)2(aq)→Ni(OH)2 (s)+ 2 NaNO3(aq)

Q: If 16.5 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₃)₂, how many grams of Ni(OH)₂ will be formed…

A: The balanced reaction given is  2 NaOH(aq) + Ni(NO₃)₂(aq) → Ni(OH)₂ (s) + 2 NaNO₃ (aq) Given : Mass…

Q: What quantity in moles of precipitate will be formed when 100.0 mL of 2.00 M NaI is reacted with…

A:

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.800 M Co(NO₃)₂ reacts with 21.0 mL of…

A: The given chemical reaction is as follows: CoNO32(aq) + 2NaOH(aq) → Co(OH)2(s) + 2NaNO3(aq) The…

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.