What lump sum do parents need to deposit in an account earning 6%, compounded monthly, so that it will grow to $100,000 for their son's college fund in 10 years? (Round your answer to the nearest cent.)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Educational Content: Compound Interest Calculation

**Problem Statement:**

What lump sum do parents need to deposit in an account earning 6%, compounded monthly, so that it will grow to $100,000 for their son's college fund in 10 years? (Round your answer to the nearest cent.)

**Solution Guide:**

To solve this problem, you will use the formula for compound interest:

\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \]

Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (initial deposit).
- \( r \) is the annual interest rate (decimal).
- \( n \) is the number of times that interest is compounded per year.
- \( t \) is the time in years.

In this scenario:
- \( A = 100,000 \)
- \( r = 0.06 \)
- \( n = 12 \) (monthly compounding)
- \( t = 10 \)

**Instructions:**
- Substitute the given values into the formula to solve for \( P \).
- Rearrange the formula to find \( P \):
  
  \[ P = \frac{A}{\left(1 + \frac{r}{n}\right)^{nt}} \]

- Calculate the result and round to the nearest cent.

### Conclusion:

By following the steps above, you will determine the exact lump sum required to reach the savings goal in 10 years. Consider using a calculator for precision.
Transcribed Image Text:### Educational Content: Compound Interest Calculation **Problem Statement:** What lump sum do parents need to deposit in an account earning 6%, compounded monthly, so that it will grow to $100,000 for their son's college fund in 10 years? (Round your answer to the nearest cent.) **Solution Guide:** To solve this problem, you will use the formula for compound interest: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] Where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount (initial deposit). - \( r \) is the annual interest rate (decimal). - \( n \) is the number of times that interest is compounded per year. - \( t \) is the time in years. In this scenario: - \( A = 100,000 \) - \( r = 0.06 \) - \( n = 12 \) (monthly compounding) - \( t = 10 \) **Instructions:** - Substitute the given values into the formula to solve for \( P \). - Rearrange the formula to find \( P \): \[ P = \frac{A}{\left(1 + \frac{r}{n}\right)^{nt}} \] - Calculate the result and round to the nearest cent. ### Conclusion: By following the steps above, you will determine the exact lump sum required to reach the savings goal in 10 years. Consider using a calculator for precision.
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